Answer:
a) V_f = 25.514 m/s
b) Q =53.46 degrees CCW from + x-axis
Explanation:
Given:
- Initial speed V_i = 20.5 j m/s
- Acceleration a = 0.31 i m/s^2
- Time duration for acceleration t = 49.0 s
Find:
(a) What is the magnitude of the satellite's velocity when the thruster turns off?
(b) What is the direction of the satellite's velocity when the thruster turns off? Give your answer as an angle measured counterclockwise from the +x-axis.
Solution:
- We can apply the kinematic equation of motion for our problem assuming a constant acceleration as given:
V_f = V_i + a*t
V_f = 20.5 j + 0.31 i *49
V_f = 20.5 j + 15.19 i
- The magnitude of the velocity vector is given by:
V_f = sqrt ( 20.5^2 + 15.19^2)
V_f = sqrt(650.9861)
V_f = 25.514 m/s
- The direction of the velocity vector can be computed by using x and y components of velocity found above:
tan(Q) = (V_y / V_x)
Q = arctan (20.5 / 15.19)
Q =53.46 degrees
- The velocity vector is at angle @ 53.46 degrees CCW from the positive x-axis.
The stone on the celestial body will be 50 N in weight. When the mass of a celestial body equals half of the mass of the earth.
<h3 /><h3>What is the difference between mass and weight?</h3>
The mass of the body is defined as the amount of matter a body has. It is denoted by m and its unit is kg.
Weight is defined as the amount of force an object exerts on the surface. It is given as the product of mass and the gravitational pull.
Given data:
The weight of the body on earth is found as;
Substitute all the values:
Hence, the weight of the stone on the heavenly body will be 50 N.
To learn more about the mass refer to the link;
brainly.com/question/19694949
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Answer:
7. 2 kg
8. 0.5 kg
9. 4 kg
Explanation:
The equation is F=MA
where F is force in Newtons
M is mass in kg
A is acceleration in m/s^2
for each you substitute in the F and A, and you are finding M. Meaning you divide F by A.
M = F/A
6/3 = 2
6/12 = 0.5
20/5 = 4