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marishachu [46]
3 years ago
5

uphill at a rate of 2.5 mi/h from the base of a 6-mi trail. At the same time, Edwin walks downhill at a rate of 3.5 mi/h from th

e top of the trail. How many hours pass before they meet on the trail?
Physics
1 answer:
uranmaximum [27]3 years ago
4 0
<h2>After 1 hour they meet.</h2>

Explanation:

Distance between them = 6 miles

Speed of uphill person = 2.5 miles per hour

Speed of downhill person = 3.5 miles per hour

Relative velocity = 2.5 - ( -3.5 ) = 6 miles per hour

We know

         Displacement = Velocity x Time

         6 = 6 x Time taken

Time taken = 1 hour

After 1 hour they meet.

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<h2>\bf{ \underline{Given:- }}</h2>

\sf• \: The \:  current \:  in \:  a \:  circuit \:  is  \: 5 \: amps.  \: and  \: resistance \:  is \:  30 \:  Ohms.

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<h2>\bf{ \underline{To \:  Find :- }}</h2>

\sf{• \:  The  \: Potential  \: Difference. }

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\huge\bf{ \underline{ Solution:- }}

\sf According  \: to  \: the  \: question,

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