Answer:
(a)The work done by the man is -15.03J.
(b)The force exerted on the object is 127.4N.
Explanation:
Mass of the object pulled by the man is -13kg
Object is lifted 11.8 cm vertical with his teeth it means (displacement = +11.8cm = +0.118m)
Acceleration due to gravity is 
(a) <u>Calculating the work done</u>:
Work done = mgh
Where "m" is mass of an object, "g" is acceleration due to gravity and "h" is the displacement.
The work done by the man is -15.03J.
(b) <u>Calculating the force</u>:
Probably the man and the object are close to the exterior of the earth. If the rigidity required to maintained the object of consistent velocity interior the gravitational field of the earth is 
Thus the weight of the object is balanced by the force of the man's teeth on the object. That is
F = mg
F = 127.4N
The force exerted on the object is 127.4N.
Answer: 0.683
Explanation: The relationship between a car moving along a curve and the frictional force is given below as
us×g = v²/r
Where us = coefficient of static friction =?, g = acceleration due to gravity = 9.8 m/s², v = 22.4 m/s and r = 75m
By substituting the parameters, we have that
us×9.8 = 22.4²/ 75
us ×9.8 = 501.76/75
us ×9.8 = 6.690
us = 6.690/9.8 = 0.683
Answer:
Explanation:
<u>Densidad</u>
La densidad de una masa m que ocupa un volumen v se define como:
Tenemos que una masa de 80 gr hace que un volumen de agua se desplace desde 60 cm3 hasta 75 cm3, es decir, el volumen propio de la masa es m = 75 - 60 = 15 cm3.
Con esta información se calcula la densidad:
Operando:
Answer:
The two possible frequencies of the other player's note are 437.3 Hz and 442.7 Hz
Explanation:
Given Data
f₁=440 Hz
fₐ=2.7 beats per seconds
The beat frequency is equal to the difference in the frequencies of the two original waves:
So
f
=|(f₁±fₐ)|
First to Solve for (-) Sign we get
f=|(440-2.7)|
f=437.3 Hz
Now for Solve for (+) Sign we get
f=|(440+2.7)|
f=442.7 Hz
The two possible frequencies of the other player's note are 437.3 Hz and 442.7 Hz
Multiple point of origin & pour pattern
