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Nataly [62]
3 years ago
12

Crust describes the outermost shell of a terrestrial planet. Earth’s crust is relatively thin, just 40-kilometers (25-miles) dee

p. Earth's crust can be divided into two types: continental and oceanic. How do these two types of crust differ? All BUT ONE could apply.
Physics
1 answer:
Anni [7]3 years ago
4 0

Answer:

"Crust" refers to a

terrestrial planet's outermost surface.

In general, the Earth's crust is divided into

older, thicker continental crust and younger, denser oceanic crust.

...

The thin, 40-kilometer (25-mile) deep crust of our planet — just

1 per cent of Earth's mass — contains all known universe existence.

Explanation:

Continental crust is thicker, 22 miles (35 km) on average and less dense than oceanic crust, which accounts for its mean surface elevation of about 3 miles (4.8 km) above that of the ocean floor (Archimedes’ principle). Continental crust is more complex than oceanic crust…

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The distance between two particles is 2 centimeters. If the distance is increased to 4 centimeters, the force will be ?
postnew [5]

Answer:

The new force is 1/4 of the previous force.

Explanation:

Given

Initial\ Distance = 2cm ---- r_1

New\ Distance = 4cm --- r_2

Required

Determine the new force

Let the two particles be q1 and q2.

The initial force F1 is:

F_1 = \frac{kq_1q_2}{r_1^2} --- Coulomb's law

Substitute 2 for r1

F_1 = \frac{kq_1q_2}{2^2}

F_1 = \frac{kq_1q_2}{4}

The new force (F2) is

F_2 = \frac{kq_1q_2}{r_2^2}

Substitute 4 for r2

F_2 = \frac{kq_1q_2}{4^2}

F_2 = \frac{kq_1q_2}{4*4}

F_2 = \frac{1}{4}*\frac{kq_1q_2}{4}

Substitute F_1 = \frac{kq_1q_2}{4}

F_2 = \frac{1}{4}*F_1

F_2 = \frac{F_1}{4}

The new force is 1/4 of the previous force.

3 0
3 years ago
An Alaskan rescue plane traveling 41 m/s
densk [106]

Answer:

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Explanation:

Given:

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Find: v

v² = v₀² + 2aΔy

v² = (0 m/s)² + 2 (-9.8 m/s²) (-165 m)

v = -56.9 m/s

8 0
4 years ago
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prohojiy [21]

Answer:

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D) There will be less available for other living things.

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