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Firdavs [7]
4 years ago
5

A football punter accelerates a .55 kg football

Physics
1 answer:
Ronch [10]4 years ago
5 0

Answer:

17.6 N

Explanation:

The force exerted by the punter on the football is equal to the rate of change of momentum of the football:

F=\frac{\Delta p}{\Delta t}

where

\Delta p is the change in momentum of the football

\Delta t=0.25 s is the time elapsed

The change in momentum can be written as

\Delta p = m(v-u)

where

m = 0.55 kg is the mass of the football

u = 0 is the initial  velocity (the ball starts from rest)

v = 8.0 m/s is the final velocity

Combining the two equations and substituting the values, we  find the force exerted on the ball:

F=\frac{m(v-u)}{\Delta t}=\frac{(0.55)(8.0-0)}{0.25}=17.6 N

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Two sources of error and precaution in the centre of gravity experiment​
Karo-lina-s [1.5K]

Answer:

The answer to this question is given below in this explanation sections.

Explanation:

The weight of an object is concentrated at the center of gravity.The term center of gravity is used interchangeably with center of mass.For a symmetrical object the center of mass is located  at the geometric  center of the object.If the object is not symmetric we can determined the center of mass using the mentioned below.

Materials:

  • cardboard
  • weight(washer,bolt,or fishing weight)
  • hole punch
  • pencil

Procedure:

  1. Cut the cardboard into a strange shape.Do not use a circle,square,rectangle,or any other common geometric shape.
  2. Punch a hole near the edge of the cut-out cardboard piece and hang it from a nail.
  3. Place the weight, a washer or bolt, on a thread and tie it off.
  4. Hang the thread and weight from the nail in front of the cardboard.
  5. use a pencil to draw a plumb line down the cardboard where the thread touches.This mark your center  line from that hanging point.

conclusion:

             What would happen to the center of gravity of the shape if you were to spin it freely?

center of gravity experiment:

  1. Balance a ruler with a hammer.Take a rubber band or string and make a loose loop around the hammer and ruler. Make sure the end of the hammer is touching the ruler,and then positions the ruler at the edge of the table.
  2. Balance two forces with  a toothpick.A common magic  trick using the properties of center of gravity.The two forks are balanced on the edge of the glass by a toothpick.
  3. Stand with your back and feet against a wall.Have someone place quarter on the floor at your feet.Try to pick it cup.Most people cant make these adjustments.
  4. Stand against a wall sideways with your arm and leg touching the wall,with nothing to from the out away hold onto.Try to lift your other leg straight out away from the wall.you wont be able to do it.
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7 0
3 years ago
Cold air masses tend to originate from: Question 3 options: tropical areas an area where it's wintertime an area where it's summ
suter [353]

Answer:

Polar areas

Explanation:

From what I know Arctic, Antarctic, and polar air masses are cold.  Polar (cold), Arctic (very cold), Equatorial (warm and very moist), and Tropical (warm).

  • With the options you gave, you can immeditaly elimate 1. tropical areas and 2. an area where its summertime.
  • Your then left with two options 1. an area where its wintertime and 2. polar areas

I then concluded that cold air masses tend to originate from POLAR AREAS.

6 0
2 years ago
Read 2 more answers
How can you tell that toast is not warmed up by conduction?
solmaris [256]

Answer:

Toasting in a toaster is usually considered  by (infra red) radiation. But the hot coils touch the toast so an element of heating by conduction occurs as well.

Explanation:

8 0
3 years ago
Which is an example of a chemical change?
Monica [59]

Answer:

Frying an Egg

Explanation:

When chemical bonds are broken or formed, new particles are created. Therefore, frying an egg is a chemical change because it results in the formation of new particles.

3 0
3 years ago
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El monoxido de carbono reacciona con el hidrogeno gaseoso para producir metanol (ch3oh) calcule el reactivo limite y el reactivo
Orlov [11]

Answer:

Se obtienen 2,27 gramos de metanol.

Explanation:

La reacción entre monóxido de carbono e hidrógeno para producir metanol es la siguiente:

CO + 2H₂ → CH₃OH  

Para encontrar el reactivo limitante y el reactivo en exceso, debemos calcular el número de moles de CO y H₂:

\eta_{CO} = \frac{m}{M}              

En donde:    

m: es la masa

M: es el peso molecular  

\eta_{CO} = \frac{m}{M_{CO}} = \frac{2,0 g}{28,01 g/mol} = 0,071 moles

\eta_{H_{2}} = \frac{2,0 g}{2,02 g/mol} = 0,99 moles

Dado que la relación estequiométrica entre CO y H₂ es 1:2, el número de moles de hidrógeno gaseoso que reaccionan con el monóxido de carbono es:

\eta_{H_{2}} = \frac{2}{1}*0,071 = 0,142 moles      

Entonces, se necesitan 0,142 moles de H₂ para reaccionar con 0,071 moles de CO y debido a que se tienen más moles de H₂ (0,99 moles) entonces el reactivo limitante es CO y el reactivo en exceso es H₂.

Ahora podemos encontar la masa de metanol obtenida usando el reactivo limitante (CO) y sabiendo que la realcion estequiométrica entre CO y CH₃OH es 1:1.    

\eta_{CH_{3}OH} = \eta_{CO} = 0,071 moles

m = 0,071 moles*32,04 g/mol = 2,27 g

Por lo tanto, se obtienen 2,27 gramos de metanol.

Espero que te sea de utilidad!      

6 0
3 years ago
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