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Veseljchak [2.6K]
2 years ago
6

Solve.

Mathematics
1 answer:
yarga [219]2 years ago
5 0
- 3/5x + 15 > 720
- 3/5x > 705
X < -423
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Write the multiplicative inverse of 1.725. Enter your answer as a fraction in its simplest form. The multiplicative inverse of 1
Katarina [22]
Multiplicative inverse is a number which when multiplied with the current number, the answer unit (that is, 1).

Now,
1.725 = 1725/1000 = 69/40

Inverting this and multiplying it with the results yields 1. That is,

69/40*40/69 = 1
Therefore, the multiplicative inverse of 1.725 is 40/69
8 0
3 years ago
En un triangulo ABC, el angulo B mide 64° y el angulo C mide 72°. La bisectriz interior CD corta a la altura BH y a la bisectriz
nadezda [96]

Answer:

The difference between the greatest and the smallest angle of the triangle PBQ is 98°.

Step-by-step explanation:

The question is:

In a triangle ABC, angle B measures 64 ° and angle C measures 72°. The inner bisector CD intersects the height BH and the bisector BM at P and Q respectively. Find the difference between the greatest and the smallest angle of the triangle PBQ.

Solution:

Consider the triangle ABC.

The measure of angle A is:

angle A + angle B + angle C = 180°

angle A = 180° - angle B - angle C

             = 180° - 72° - 64°

             = 44°  

It is provided that CD and BM are bisectors.

That:

angle BCP = angle PCH = 36°

angle CBQ = angle QBD = 32°

angle BHC = 90°

Compute the measure of angle HBC as follows:

angle HBC = 180° - angle BHC + angle BCH

                  = 180° - 90° - 72°

                  = 18°

Compute the measure of angle BPC as follows:

angle BPC = 180° - angle PCB + angle CBP

                  = 180° - 18° - 36°

                  = 126°

Then the measure of angle BPQ will be:

angle BPQ = 180° - angle BPC

                  = 180° - 126°

angle BPQ = 54°

Compute the measure of angle PBQ as follows:

angle PBQ = angle B - angle QBD - angle HBC

                  = 64° - 32° - 18°

angle PBQ = 14°

Compute the measure of angle BQP as follows:

angle BQP = 180° - angle PBQ - angle BPQ

                  = 180° - 14° - 54°  

angle BQP = 112°

So, the greatest and the smallest angle of the triangle PBQ are:

angle BQP = 112°

angle PBQ = 14°

Compute the difference:

<em>d</em> = angle BQP - angle PBQ

  = 112° - 14°

  = 98°

Thus, the difference between the greatest and the smallest angle of the triangle PBQ is 98°.

4 0
3 years ago
Find cp if so =rs 800 and loss% = 10%​
rjkz [21]

Step-by-step explanation:

Sp = rs 800

loss = 10%

Cp = ?

we know that,

cp= sp×100÷ 100-L%

= 800×100÷100-10

= 80000÷90

= 888.89#

3 0
2 years ago
Read 2 more answers
I dont know how to find the answer
sleet_krkn [62]

Answer:

a rotation followed by a translation

Step-by-step explanation:

i took the class last trimester

4 0
2 years ago
What is -3/4(2/3 in simplest form
Tanya [424]

Answer:

-1/2 or the decimal form -0.5

7 0
2 years ago
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