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BigorU [14]
3 years ago
6

What is 5/6 closer to

Mathematics
2 answers:
iogann1982 [59]3 years ago
3 0
5/6 is closer to 10/16.
Nimfa-mama [501]3 years ago
3 0
5/6 is closer to one because it is only 1/6 away from 1(found by subtracting 5/6 by 1/1), but it is 5/6 away 0, and it is 2/6 away from 1/2( found by subtracting 5/6 - 1/2 because 1/2 is equal to 3/6).    Hope that makes sense!
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An angle is 6 more than five times its supplement. Find the measure of the largest angle.
Julli [10]
Supplementary angles add up to 180°


Angle y is the large angle: y= 5x+6

180= x+y
180= (5x+6) + x
180=6x+6
174=6x
x=29

180= y+29
y=151°
4 0
3 years ago
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How many x -intercepts does the parabola whose function is f(x)=3 x 2 +4x+4
artcher [175]

Answer:

They are none x- intercepts on the parabola. To find the x-intercept, substitute in 0 for y and solve for x.

3 0
3 years ago
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Please help me stats
Korolek [52]
The answer is A.....
5 0
3 years ago
The length and width of a rectangle are measured as 55 cm and 49 cm, respectively, with an error in measurement of at most 0.1 c
valentina_108 [34]

Answer:

The maximum error in the calculated area of the rectangle is 10.4 \:cm^2

Step-by-step explanation:

The area of a rectangle with length L and width W is A= L\cdot W so the differential of <em>A</em> is

dA=\frac{\partial A}{\partial L} \Delta L+\frac{\partial A}{\partial W} \Delta W

\frac{\partial A}{\partial L} = W\\\frac{\partial A}{\partial W}=L so

dA=W\Delta L+L \Delta W

We know that each error is at most 0.1 cm, we have |\Delta L|\leq 0.1, |\Delta W|\leq 0.1. To find the maximum error in the calculated area of the rectangle we take \Delta L = 0.1, \Delta W = 0.1 and L=55, W=49. This gives

dA=49\cdot 0.1+55 \cdot 0.1

dA=10.4

Thus the maximum error in the calculated area of the rectangle is 10.4 \:cm^2

4 0
3 years ago
How would I get to X. Please show work
Bond [772]
Well I can’t see where x would be therefore I can’t tell you how to get to x
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3 years ago
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