Question

Given tanB = 15/9 find angle B in degrees. Round your answer to the nearest hundredth.

Answer 1

Given

$\tan(B)=\frac{15}{9}$

This is the same as

$\tan(B)=\frac{5}{3}$

Take arctangent of both sides

$B=arctan( \frac{5}{3})$

$B=59.03624347$

Rounding to the nearest hundredth means round to two decimal places

$B=59.04\degree$