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3 years ago

Early U.S. rocket technology was based in part on information taken from German V-2 rockets.

Physics

2 answers:

yKpoI14uk [10]3 years ago

5 0

True.. hope it helps :)

Digiron [165]3 years ago

5 0

Answer:

True

Explanation:

Although the rocket science and use of rockets in warfare goes back centuries, a great shift in the progress of rocket science occurred after the end of World War 2. During the World War 2, a lot of improvement was done in the rockets but it was mainly for the military purpose.

German scientist Wernher von Braun played a crucial role in development of V2, the first rocket capable of entering into SPACE if launched vertically. After the end of World War 2, US captured von Braun and other German rocket scientists and brought them to US and started Operation Paperclip. The technology of V2 rockets was used to develop the early USA rocket: Redstone rocket.

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Answer:

the answer to this question is 288

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3 years ago

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valkas [14]

Answer:

0.72 kg per cubic m

Explanation:

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3 years ago

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saw5 [17]

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3 years ago

Read 2 more answers

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nignag [31]

Answer:

Two rocks of equal mass fall to the ground at the same speed.

Explanation:

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4 years ago

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A proton is moving in a circular orbit of radius 20 cm under a uniform magnetic field 0.3 t perpendicular to the velocity of the

Vladimir [108]

Answer:

v = 5.75 x 10⁶ m/s

Explanation:

The radius (r) of the circular orbit taken by a charged particle is related to its speed perpendicular to a magnetic field of strength B, and is given by

r = $\frac{mv}{qB}$ --------------(i)

Where,

q = charge of the particle

m = mass of the particle

Making v subject of the formula in equation (i) above gives

v = $\frac{qBr}{m}$ -------------------(ii)

Given;

r = 20cm = 0.2m

B = 0.3T

v = unknown

q = charge of proton = 1.6 x 10⁻¹⁹ C

m = mass of the proton = 1.67 x 10⁻²⁷kg

Substitute the values of m, q, B and r into equation (ii) above to get;

v = $\frac{1.6 * 10^{-19} * 0.3 * 0.2} {1.67*10^{-27} }$

Solving for v gives:

v = 5.75 x 10⁶ m/s

Therefore, the velocity of the proton is 5.75 x 10⁶ m/s

4 0

3 years ago