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Vlad [161]
3 years ago
9

Which result is more accurate: the slope or the mean value

Physics
1 answer:
Grace [21]3 years ago
7 0
I think it is the mean as it gives more of an accurate result. Please give brainiest and thanks
You might be interested in
un cilindro uniforme empujado por una tabla desde una posicion inicial mostrada en la figura, rueda hacia delante por el suelo,
Andreyy89

Answer:

L/2.

Explanation:

Hola.

En este caso, dado que el hombre empuja el cilindro desde el punto L=0 y hasta la mitad de la longitud entre el hombre y el cilindro, es claro que el cilindro se desplaza un L/2 más de la distancia inicial entre el hombre y el cilindro, de este modo, inferimos que el hombre también ha caminado L/2.

¡Saludos!

5 0
4 years ago
Blue bumper car, traveling east with a force of 100 N, runs into a yellow bumper car traveling west with a force of 300 N. Becau
Pani-rosa [81]

Answer:

the blue bumper car

Explanation:

because the yellow bumper car is coming in with much more force

and according to Newton, actions and reactions are equal and opposite, so the yellow bumper car will five out 300N while the blue car will give out only 100N

then it almost because a fight between 300N vs 100N

and obviously, the 300N will win and the 100N will be pushed back

4 0
3 years ago
An object that is dropped from a height H falls with a constant acceleration of g. The final
GuDViN [60]

The height need to change by 4 to double the final velocity.

<h3>Final velocity of the object</h3>

The final velocity of an object during a free fall is related to maximum height of fall as given the equation below.

v = √2gh

v² = 2gh

v²/h = 2g

v₁²/h₁ = v₂²/h₂

when v₂ = 2v₁, change in height is calculated as;

h₂ = h₁v₂²/v₁²

h₂ = (h₁ (2v₁)²) / (v₁)²

h₂ = 4h₁v₁² / v₁²

h₂ = 4h₁

Thus, the height need to change by 4 to double the final velocity.

Learn more about final velocity here: brainly.com/question/25905661

#SPJ1

4 0
2 years ago
a plane is flying due east in still air at 395 km/h. suddenly, the plane is hit by wind blowing at 55km/h toward the west. what
Sphinxa [80]
Let's be clear:  The plane's "395 km/hr" is speed relative to the
air, and the wind's "55 km/hr" is speed relative to the ground.

Before the wind hits, the plane moves east at 395 km/hr relative
to both the air AND the ground.

After the wind hits, the plane still maintains the same air-speed.
That is, its velocity relative to the air is still 395 km/hr east.
But the wind vector is added to the air-speed vector, and the
plane's velocity <span>relative to the ground drops to 340 km/hr east</span>.

6 0
4 years ago
You are in your car driving on a highway at 23 m/s when you glance in the passenger-side mirror (a convex mirror with radius of
Irina-Kira [14]

Answer:

v = 26. 88 m/s +23 m/s

Explanation:

u = 23 m/s, r = 150 cm, u₁ = 2.0 m/s, s =2.0 m

\frac{1}{s} +\frac{1}{s'} = \frac{2}{R}

\frac{1}{2.0 m} +\frac{1}{s'} = \frac{2}{1.50 m}

Solve s'

\frac{1}{s'}  = \frac{2}{1.50 m} - \frac{1}{2.0 m}

\frac{1}{s'} =  1.833 m

s' = - 0.545 m

To determine the speed of the trick to the highway

\frac{ds}{dt}= \frac{s^2* \frac{ds}{dt}}{s' ^2} =\frac{2.0 ^2m * 2.0 m/s}{0.545^2m}

\frac{ds}{dt} = 26.88 m/s

Now to determine the velocity highway is going to be

v = ds/dt + u

v = 26. 88 m/s +23 m/s

8 0
4 years ago
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