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GenaCL600 [577]
3 years ago
7

Most stable monatomic ion formed from fluorine

Chemistry
1 answer:
choli [55]3 years ago
4 0

<em>hope this helped ;-;</em>

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What happens when you mix acid and base?
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Does it require more force to stop a bus or a bike moving at the same speed
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7 0
4 years ago
Which of the following reagents is/are likely to be used to form the Britton–Robinson buffer solution used in the experiment?
Ierofanga [76]

Answer:

I. A polyprotic, weak acid

II. Na2HPO4

Explanation:

Buffer solutions are those that, upon the addition of an acid or base, are capable of reacting by opposing the part of the basic or acid component to keep the pH fixed.

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A buffer acid reacts when a weak acid or weak base is combined with its corresponding hydrolytic salt in a water solution, a buffer system called a buffer is formed. As in this case a weak polyrotic acid with Na2HPO4, which allows the solution to be maintained at a pH of 3.8 against small aggregate amounts of both acid and base, thus favoring the reaction at a pH of 3.8

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4 0
3 years ago
What is the mass, in grams, of a sample of 6.98 × 1024 atoms of magnesium (Mg)? Show your work or explain the steps that you use
CaHeK987 [17]

Hello!

* First Step: to know Avogrado's Law

We know that by the Law of Avogrado, for each mole of substance we have 6.02*10²³ atoms, if:

** Second Step: to know the molar mass of the solute

The molar mass of of magnesium = 24.30 g/mol

*** Third step: make the ratio mass / mol with atoms

1 mol we have 6.02*10²³ atoms

1 mole of Mg we have 24.30 g

Then we have:

24.30 g ------------- 6.02*10²³ atoms

x ----------------------- 6.98*10^24 atoms

\dfrac{24.30}{x} = \dfrac{6.02*10^{23}}{6.98*10^{24}}

multiply cross

6.02*10^{23}*x = 24.30*6.98*10^{24}

6.02*10^{23}\:x = 1.69614*10^{26}

x = \dfrac{1.69614*10^{26}}{6.02*10^{23}}

\boxed{\boxed{x \approx 281.75\:grams}}\end{array}}\qquad\checkmark

I Hope this helps, greetings ... DexteR! =)

7 0
3 years ago
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