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svet-max [94.6K]
1 year ago
15

What mass of kcl in grams must be added to 500 ml of a 0. 15 m kcl solution to produce a 0. 40 m solution.

Chemistry
1 answer:
iren [92.7K]1 year ago
3 0

91.4 grams

91.4 grams of kcl in grams must be added to 500 ml of a 0. 15 m kcl solution to produce a 0. 40 m solution.

C = mol/volume

2.45M=mol/0.5L

2.45M⋅0.5L = mol

mol = 1.225

Convert no. of moles to grams using the atomic mass of K + Cl

1.225mol * \frac{39.1+35.5}{mol}

mol=1.225

=1.225 mol . \frac{74.6g}{mol}

=1.225 . 74.6

=91.4g

therefore, 91.4 grams of kcl in grams must be added to 500 ml of a 0. 15 m kcl solution to produce a 0. 40 m solution.

What is 1 molar solution?

In order to create a 1 molar (M) solution, 1.0 Gram Molecular Weight of the chemical must be dissolved in 1 liter of water.

58.44 g make up a 1M solution of NaCl.

To learn more about molar solution visit:

brainly.com/question/10053901

#SPJ4

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Answer:

7430.5 Joules (7.4*10^4 Joules)

Explanation:

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Now m=250 g

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7 0
3 years ago
A gas fills a balloon at a temperature of 27 C and 101.325 kPa of pressure. What will the pressure of the balloon be if the gas
JulijaS [17]

135.1‬kPa

Explanation:

Given parameters:

T1 = 27°C

P1  = 101.325 kPa

T2 = 127°C

Unknown:

P2 = ?

Solution:

Using a derivative of the combined gas law where we assume that the gas has a constant volume, we can solve for the unknown.

 At constant volume:

           \frac{P1}{T1}  = \frac{P2}{T2}

P1 is the initial pressure

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P2 is the final pressure

T2 is the final temperature

  Take the given temperature to K

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    \frac{101.325}{300}  = \frac{P2}{400}

  P2 = 135.1‬kPa

learn more:

Boyle's law brainly.com/question/8928288

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