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Nady [450]
3 years ago
10

Which of the

Chemistry
2 answers:
saul85 [17]3 years ago
6 0

Answer:

During chemical reactions, matter is neither

created nor destroyed; it just changes form.

Explanation:

MariettaO [177]3 years ago
3 0

Answer:

the second one.

Explanation:

it just changes.

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Commercially available concentrated sulfuric acid is 17.2M . Calculate the volume of concentrated sulfuric acid required to prep
Dimas [21]

Answer:

0.727 l.

Explanation:

For the new dilute Sulphuric acid,

Number of moles = molar concentration × volume

= 2.5 × 5

= 12.5 mol

Volume of concentrated solution = 12.5/17.2

= 0.727 l of 17.2 M of sulphuric acid to be diluted.

5 0
3 years ago
Given that the initial rate constant is 0.0110s−1 at an initial temperature of 21 ∘C , what would the rate constant be at a temp
gulaghasi [49]

The rate constant is mathematically given as

K2=2.67sec^{-1}

<h3>What is the Arrhenius equation?</h3>

The rate constant for a particular reaction may be calculated with the use of the Arrhenius equation. This constant can be stated in terms of two distinct temperatures, T1 and T2, as follows:

ln(\frac{K2}{K1})= (\frac{Ea}{R})*(\frac{1}{T1}-\frac{1}{T2})

Therefore

KT1= 0.0110^{-1}

T1= 21+273.15

T1= 294.15K

T2= 200  

T2=200+273.15

T2= 473.15K

Ea= 35.5 Kj/Mol

Hence, in  j/mol R Ea is

Ea=35.5*1000 j/mol R

ln(\frac{K2}{0.0110})= (\frac{35.5*1000}{8.314})*(\frac{1}{294.15}-\frac{1}{473.15}\\\\ln(\frac{K2}{0.0110})=5.492

K2/0.0110 =e^(5.492)

K2/0.0110 =242.74

K2= 242.74*0.0110

K2=2.67sec^{-1}

In conclusion, rate constant

K2=2.67sec^{-1}

Read more about rate constant

brainly.com/question/20305871

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5 0
2 years ago
Atom A has five protons, four neutrons, and five electrons. Atom
Anna35 [415]

Answer:

they are the same element because they have the same number of protons and electrons,but a different number of neutrons

6 0
3 years ago
A local farmer notices that the level of water in the pond behind his house has been going down. Temperatures have been very hig
nikitadnepr [17]

EVAPORATION OR THE ANIMALS ARE DRINKING THE WATER BECAUSE IT IS HOT

6 0
3 years ago
How many grams of cupric sulfate pentahydrate are needed to prepare 50.00 mL of 0.0800M CuSO4× 5H2O?
shepuryov [24]

Explanation:

Molarity is defined as number of moles per liter of solution.

Mathematically,         molarity = \frac{no. of moles}{Volume (in L) of solution}

It is given that molarity is 0.0800 M and volume is 50.00 mL or 0.05 L.

           molarity = \frac{no. of moles}{Volume of solution in liter}

            0.0800 M = \frac{no. of moles}{0.05 L}

            no. of moles = 1.6 mol

Therefore, molar mass of cupric sulfate pentahydrate is 249.68 g/mol. So, calculate the mass as follows.

                No. of moles = \frac{mass in grams}{molar mass}

             mass in grams = no. of moles \times molar mass of CuSO_{4}.5H_{2}O

                                       = 1.6 mol \times 249.68 g/mol

                                       = 399.488 g

Thus, we can conclude that 399.488 g of cupric sulfate pentahydrate are needed to prepare 50.00 mL of 0.0800M CuSO4× 5H2O.

4 0
3 years ago
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