Question

Can someone help me I begging you all see this please

Answer 1

Answer:

26. Mass of sugar = 100 g

27. a).m/m % = 8.67 %

     b).m/m% = 20%

28.a). Mass of sugar = 12.5 g

     b).Mass of sugar = 12.5 g

     c).Mass of sugar = 30 g

Explanation:

26. Use formula:

$m/m = \frac{mass\ of\ solute}{mass\ of\ solution} \times 100$

m/m = 20%

mass of solution = 500 g

mass of Solute = mass of sugar = ?

insert in the formula,

$20 = \frac{mass\ of\ solute}{500} \times 100$

$mass\ of\ solute = 20 \times 5$

mass of solute = 100 g

27. a)

$m/m = \frac{mass\ of\ solute}{mass\ of\ solution} \times 100$

mass of Barium hydroxide(solute) = 13 g

mass of solution = 150 g

$m/m = \frac{13}{150} \times 100$

m/m % = 8.67 %

b).

$m/m = \frac{mass\ of\ solute}{mass\ of\ solution} \times 100$

mass of Glucose (solute) = 50 g

mass of solution = 250 g

$m/m = \frac{50}{250} \times 100$

m/m% = 20%

28. a)

$m/m = \frac{mass\ of\ solute}{mass\ of\ solution} \times 100$

m/m% = 5

mass of solution = 250 g

mass of solute = ?

$mass\ of\ solute= \frac{mass\ of\ solution}{100} \times m/m$

$mass\ of\ solute= \frac{250}{100} \times 5$

mass of sugar = 12.5 g

b).

m/m% = 2.5%

mass of solution = 500 g

mass of solute = ?

$mass\ of\ solute= \frac{mass\ of\ solution}{100} \times m/m$

$mass\ of\ solute= \frac{500}{100} \times 2.5$

mass of sugar = 12.5 g

c).

m/m% = 3 %

mass of solution = 1 kg = 1000 g

mass of solute = ?

$mass\ of\ solute= \frac{1000}{100} \times 3$

Mass of sugar = 30 g