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3 years ago

Graph this equation y=7/2x-2

Mathematics

1 answer:

Ludmilka [50]3 years ago

6 0

To find the slope and y intercept, use the y=mx+b formula where m is the slope and b is the y intercept.
y=mx+b

Pull the values of m and b using the y=mx+b formula.
m=7/2,b=−2 where m is the slope and b is the y-intercept

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Factor completely 8x2 − 4x − 84. 4(2x − 3)(x 7) 4(2x 3)(x − 7) 4(x − 3)(2x 7) 4(x 3)(2x − 7).

gizmo_the_mogwai [7]

The factor of the given equation $8x^{2} -4x-84$ will be $4(x+3)(2x-7)$

<h3>What will be the factor of the given equation?</h3>

Given equation is $8x^{2} -4x-84$

Now taking 2 commons from the equation

$4(2x^{2} -x-21)$

now splitting the equation we get

$4(2x^{2} +6x-7x-21)$

$4(2x(x+3)-7(x+3))$

$4(x+3)(2x-7)$

Thus the factor of the given equation $8x^{2} -4x-84$ will be

$4(x+3)(2x-7)$

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PLEASE HELP

Usimov [2.4K]

Answer:

$r\approx0.03\text{ or about $3\%$}$

Step-by-step explanation:

The standard compound interest formula is given by:

$\displaystyle A=P(1+\frac{r}{n})^{nt}$

Where A is the amount afterwards, P is the principal, r is the rate, n is the times compounded per year, and t is the number of years.

Since we are compounding annually, n=1. Therefore:

$\displaystyle A = P (1+r)^{t}$

Lester wants to invest $10,000. So, P=10,000.

He wants to earn $1000 interest. Therefore, our final amount should be 11000. So, A=11000.

And our timeframe is 3.3 years. So, t=3.3. Substituting these values, we get:

$11000=10000(1+r)^{3.3}$

Let’s solve for our rate r.

Divide both sides by 10000:

$1.1=(1+r)^{3.3}$

We can raise both sides to 1/3.3. So:

$\displaystyle (1.1)^\frac{1}{3.3}=((1+r)^{3.3})^\frac{1}{3.3}$

The right side will cancel:

$\displaystyle r+1=(1.1)^\frac{1}{3.3}$

So:

$\displaystyle r=(1.1)^\frac{1}{3.3}-1$

Use a calculator:

$r\approx0.03$

So, the annual rate of interest needs to be about 0.03 or 3% in order for Lester to earn his interest.

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