Answer:
Check the explanation
Explanation:
Here in this game of Tic-Tac-Toe, it is using the TPGE engine which is a Tiny Python Game Engine. Let's talk about its functions like:-
def image_type(img): In this function, it is simply taking image as a parameter and returning its object type like DISC if the image is in graphical form, TEXT if it is a string, and LINE if it is other than the mentioned object.
def convert_image(img): In this function, it is simply taking image as a parameter and returning an equivalent graphical object as understood by John Zelle's. Mainly comparing for three things in this function and those are: if image equals to DISC then it is calling convert_circle(function), if image equals to LINE then it is calling convert_line(function), and if image equals to TEXT then it is calling convert_text(function),
def convert_circle(x): This function takes a list( a group of values) and makes a circle at the center of the window and the circle's radius is coming from the list.
convert_text, convert_line, convert_circle are only creating text, line, and circle and then returning it.
def graphical_elements(images): This function is taking image as a parameter and then extracting shape and color from the image and then calling convert_image(shape) and convert_type(shape) and it gives us graphic and kind respectively. Now it is checking whether kind equals to DISC If yes then filling color on the window else, setting the outline of the window
def run(): Here it is finally running the game with required parameters, the whole game is continously running under the while loop.
That's all
Use Windows Task Manager & Resource Monitor. The easiest way to free up RAM in use is to open Windows Task Manager. Navigate to the Processes tab and then sort the list of open programs by memory. This will reveal any process that's consuming an unusually large volume of RAM.
Solution:
The process of transaction can guarantee the reliability of business applications. Locking resources is widely used in distributed transaction management (e.g; two phase commit, 2PC) to keep the system consistent. The locking mechanism, however, potentially results in various deadlocks. In service oriented architecture, the deadlock problem becomes even worse because multiple transactions try to lock shared resources in the unexpectable way due to the more randomicity of transaction requests, which has not been solved by existing research results. In this paper, we investigate how to prevent local deadlocks, caused by the resource competition among multiple sub-transactions of a gl obal transaction, and global deadlocks from the competition among different global transactions. We propose a replication based approach to avoid the local deadlocks, and a timestamp based approach to significantly mitigate the global deadlocks. A general algorithm is designed for both local and global deadlock prevention. The experimental results demonstrate the effectiveness and efficiency of our deadlock prevention approach. Further, it is also proved that our approach provides higher system performance than traditional resource allocation schemes.
This is the required answer.
Answer B: Asymmetric cryptography, because the receiver has its own decryption key and cannot create encrypted messages, because he doesn't have the encryption key.
About the other answers:
A: Private keys are always involved, there has to be some secret to do encryption, so this answer doesn't say very much.
C: Digital signatures can be used to verify/prove some data comes from some person (the signer) in an unaltered way. It is not about encryption, so is not about the security of your message. You use it in combination with encryption.
D: Like A, this doesn't say very much. Shared secret keys (symmetric keys) can be used for encryption, but they are less secure since the keys have to exist in more than one place (sender and receiver).
di = {"student":"10/30/1984", "student2":"11/16/2020"}
name = input("What is your name? ")
if name in di:
print(di[name])
else:
print("Your name is not in the dictionary.")
You can change the values inside the dictionary. I hope this helps!
