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Leni [432]
3 years ago
14

The equation of line A is y = 7x + 12. Line B is perpendicular to line A and passes through the point . What would be the soluti

on to the system of equations represented by line A and line B?
Mathematics
1 answer:
max2010maxim [7]3 years ago
3 0
Since B is perpendicular to A. We can say that the gradient of B will be -1/7 (product of the gradients of 2 perpendicular lines has to be -1).
Now we know that the equation for B is y=-(1/7)x + c with c being the y intercept.
Since the point isnt specified in the question, we could leave the equation like this.
But if there is a given point that B passes through, just plug in the x and y values into their respective places and solve to find c. That should give you the equation for b.
Now, to find the solution of x, we have 2 equations:
1) y=7x+12
2)y=-(1/7)x+c

In this simultaneous equation we see that y is equal to both the expressions. So,
7x+12=-(1/7)x+c

Now, since the value of c is not found, we cannot actually find the value of x, but if we would find c, we could also find x since it would only be a matter of rearranging the equation.
And there you go, that is your solution :)
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$360 : $600

Step-by-step explanation:

If I'm understanding the problem right, you're looking for this to be put into a 3:5 ratio.

When doing problems like these, I'll add the two numbers in the ratio together, then divide the number (in this case 960) by the sum of the ratios, which in this case is 8.

From there you'd divide 960/8, which is 120. Based on that, you can assume 120 is equal to "1" in the ratio. Then multiply the base unit 1 by each one of the ratios.

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You get everything you need from factoring the last expression:

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