The percentage of glucose given is m/v. This means that the given percentage of volume consists of mass.
In this solution, percentage of glucose is 5.5% m/v.
This means that 5.5% of the volume is the mass of glucose.
Given volume is 285 mL.
Therefore mass of glucose is 5.50% of 285 mL = (5.5*285)/100
mass of glucose = 15.67 g
a.
A substance's specific heat tells you how much heat is required to increase the temperature of 1 g of that substance by 1°C.
The equation that establishes a relationshop between heat and change in temperature is
q = m • c • ∆T, where
q - heat absorbed
c - the specific heat of the substance, in your case of water
ΔT - the change in temperature, defined as the difference between the final temperature and the initial temperature
so:
q = 1.00 g • 4.18 J/g×°C • (75.0 - 38.5)°C
q = 152,57 J
just apply this formula for all exercises
Answer:
80.7 L
Step-by-step explanation:
This looks like a case where we can use the Ideal Gas Law to calculate the volume.
pV = nRT Divide both sides by p
V = (nRT)/p
=====
Data:
n = 5.00 mol
R = 0.082 06 L·atm·K⁻¹mol⁻¹
T = (120 +273.15) K = 393.15K
p = 1520 mmHg × 1 atm/760 mmHg = 2.00 atm
=====
Calculation:
V = (5.00 × 0.082 06 × 393.15)/2.00
V = 161.3/2.00
V = 80.7 L
