Answer:
The volume of feedstock needed to mantain an organic load rate of 2 kgVS/day is 0.055 m3/day of feedstock.
The HRT is 20.6 days.
Explanation:
First, we calculate how many kg is 1 m3 of feedstock. We know the density, so we can calculate the mass:
If the VS are 6% in weight,
The volume per day needed to feed 2 kg of VS/day is:
The HRT depends on the volume of the tank and the flow. Its equation is
Answer:
0.350 g of iron
Explanation:
Step 1: Given data
Mass of iron (m): 350 mg
Step 2: Convert the mass of iron to milligrams
In order to convert the mass of iron from grams to milligrams we need a conversion factor. In this case, the conversion factor is 1 g = 1,000 mg.
350 mg Fe × 1 g Fe/1,000 mg Fe = 0.350 g Fe
350 milligrams of iron is equal to 0.350 grams of iron. We conserve the 3 significante figures of the original data.
Answer:
The NaCl concentration will be 0.03 M.
Explanation:
Given data:
Initial volume = V₁ = 56.98 mL (56.98/1000 = 0.05698 L)
Initial concentration = M₁= 0.5894 M
Final volume = V₂= 1.20 L
Final concentration = M₂= ?
Solution:
By diluting the solution volume of solution will increase while number of moles of solute remain the same.
Formula:
Initial concentration × Initial volume = Final concentration × Final volume
M₁V₁ = M₂V₂
M₂ = M₁V₁ / V₂
M₂ = 0.5894 M × 0.05698 L / 1.20 L
M₂ = 0.0336 M /1.20
M₂ = 0.03 M
