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maks197457 [2]
4 years ago
12

How many significant figures are in 7.1 x 10-6

Chemistry
1 answer:
Iteru [2.4K]4 years ago
3 0

7.1x10=71

71-6=65

2cifrass

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A 300-gallon anaerobic digester will be loaded daily with a feedstock that contains two parts dairy manure and one-part water by
Mars2501 [29]

Answer:

The volume of feedstock needed to mantain an organic load rate of 2 kgVS/day is 0.055 m3/day of feedstock.

The HRT is 20.6 days.

Explanation:

First, we calculate how many kg is 1 m3 of feedstock. We know the density, so we can calculate the mass:

M=\rho*V=37.5\frac{lb}{ft^3}*1m^3*(\frac{3.281ft}{1m})  ^3=1324.5lb=600.7 kg

If the VS are 6% in weight,

M_{vs}=0.06*M=0.06*600.7\,kg/m^3=36,0kgVS/m3

The volume per day needed to feed 2 kg of VS/day is:

V=\frac{2kg}{36kg/m^3}= 0.055m3/day=5.5litres/day

The HRT depends on the volume of the tank and the flow. Its equation is

HRT=\frac{V}{Q}=\frac{300gal}{0.055 m^3/day}*\frac{1m^3}{264.172gal}\\   \\HRT=20.6\,days

6 0
3 years ago
People increase erosion in forested areas by
Maru [420]
Pollution ..........,
5 0
3 years ago
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How many grams of iron are in 350 mg of iron?-
Mamont248 [21]

Answer:

0.350 g of iron

Explanation:

Step 1: Given data

Mass of iron (m): 350 mg

Step 2: Convert the mass of iron to milligrams

In order to convert the mass of iron from grams to milligrams we need a conversion factor. In this case, the conversion factor is 1 g = 1,000 mg.

350 mg Fe × 1 g Fe/1,000 mg Fe = 0.350 g Fe

350 milligrams of iron is equal to 0.350 grams of iron. We conserve the 3 significante figures of the original data.

3 0
3 years ago
2) What is the concentration of NaCl in a solution prepared by diluting 56.98 ml of 0.5894 M stock
RSB [31]

Answer:

The NaCl concentration will be 0.03 M.

Explanation:

Given data:

Initial volume = V₁ = 56.98 mL (56.98/1000 = 0.05698 L)

Initial concentration = M₁= 0.5894 M

Final volume = V₂= 1.20 L

Final concentration = M₂= ?

Solution:

By diluting the solution volume of solution will increase while number of moles of solute remain the same.

Formula:

Initial concentration × Initial volume  = Final concentration × Final volume

M₁V₁ = M₂V₂

M₂ = M₁V₁ / V₂

M₂ = 0.5894 M × 0.05698 L / 1.20 L

M₂ = 0.0336 M /1.20  

M₂ = 0.03 M

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4 years ago
k4llllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllll
Westkost [7]
What is the question lol
7 0
4 years ago
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