What factors might cause population changes in grasshoppers?

9. How does water pollution contribute to water shortages?

Grace [21]

Answer:

<h2>if the chemicals seep into the groundwater or in underground aquifers.</h2><h2 />

Explanation:

<h3>One of the largest causes of water scarcity across the world is pollution. ... Pesticides and other fertilizer use by farmers can also lead to water pollution if the chemicals seep into the groundwater or in underground aquifers. The misuse of water resources is another massive issue that leads to water scarcity.</h3>

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8 0

3 years ago

A physics student stands on a cliff overlooking a lake and decides to throw a softball to her friends in the water below. She th

aliina [53]

Answer:

58.5 m

Explanation:

First of all, we need to find the total time the ball takes to reach the water. This can be done by looking at the vertical motion only.

The initial vertical velocity of the ball is

$u_y = u sin \theta$

where

u = 21.5 m/s is the initial speed

$\theta=33.5^{\circ}$ is the angle

Substituting,

$u_y = (21.5) sin 33.5^{\circ} =11.9 m/s$

The vertical position of the ball at time t is given by

$y = h + u_y t + \frac{1}{2}gt^2$

where

h = 13.5 m is the initial heigth

$g = -9.8 m/s^2$ is the acceleration of gravity (negative sign because it points downward)

The ball reaches the water when y = 0, so

$0 = h + u_yt +\frac{1}{2}gt^2\\0 = 13.5 +11.9 t - 4.9t^2$

Which gives two solutions: t = 3.27 s and t = -0.84 s. We discard the negative solution since it is meaningless.

The horizontal velocity of the ball is

$u_y = u cos \theta = (21.5) cos 33.5^{\circ} =17.9 m/s$

And since the motion along the horizontal direction is a uniform motion, we can find the horizontal distance travelled by the ball as follows:

$d= u_x t = (17.9)(3.27)=58.5 m$

3 0

3 years ago

The collision between a hammer and a nail can be considered to be approximately elastic. Estimate the kinetic energy acquired by

AlekseyPX

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3 0

4 years ago

An object has a horizontal velocity component of 6 m/s and a vertical velocity component of 4 m/s.

taurus [48]

For the object that has a horizontal velocity component of 6 m/s and a vertical velocity component of 4 m/s we have:

1. The velocity of the object is 7.21 m/s.

2. The angle it makes with the horizontal is 33.7°.

1. The velocity of the object can be found as follows:

$v = \sqrt{v_{x}^{2} + v_{y}^{2}}$

Where:

$v_{x}$ : is the horizontal component of the velocity = 6 m/s

$v_{y}$ : is the vertical component of the velocity = 4 m/s

Hence, the <u>velocity is</u>:

$v = \sqrt{v_{x}^{2} + v_{y}^{2}} = \sqrt{(6 m/s)^{2} + (4 m/s)^{2}} = 7.21 m/s$

2. The angle it makes with the <u>horizontal </u>can be calculated with the following trigonometric function:

$tan(\theta) = \frac{v_{y}}{v_{x}}$

Where:

θ: is the angle it makes with the horizontal

Therefore, the <u>angle is</u>:

$\theta = tan^{-1}(\frac{v_{y}}{v_{x}}) = tan^{-1}(\frac{4}{6}) = 33.7$

You can learn more about the components of the velocity here: brainly.com/question/2285233?referrer=searchResults

I hope it helps you!

7 0

3 years ago

Between which two points of a concave mirror should an object be placed to obtain a magnificati of -3

kobusy [5.1K]

Answer:

When object is placed between the focus (F) and pole (P) of a concave mirror, magnified and erect image of the object is formed on the back of the mirror.

When object is placed between the centre of curvature and the principal focus of a concave mirror, magnified and inverted image is formed in front of the mirror.

Explanation:

8 0

3 years ago