B.Speed of light
The speed of light is used as a reference and is 3x10^8 m/s no matter what.
Hope this helps :)
Say the horizontal component of the velocity is vx and the vertical is vy.
Initially at t=0 (as the mug leaves the bar) the components are v0x and v0y.
Obviously (I hope!) v0y = 0.
The equations for horizontal and vertical projectile motion (with the positive direction up) are
x = x0 + v0x t
y = y0 + v0y t - 1/2 g t^2 = y0 - 1/2 g t^2
Now choose the origin to be the end of the counter. x0=0 and y0=0. The equations simplify to
x = v0x t
y = - 1/2 g t^2
You know that x = 1.20m when y = -0.88m
From the y equation (and g=10 m/s^2) you can calculate the time that the mug hits the floor.
t = 0.420s
From the x equation we get the initial horizontal velocity
v0x = x/t = 1.2/0.42 = 2.86 m/s
(b) x-component of velocity is constant since there are no horizontal forces so vx = 2.86 m/s
y-component is given by v = u+at with u=0 and a=-g
vy = -gt = -4.2m/s
Now tan(angle) = vy/vx so angle = arctan(vy/vx)
Answer:
D
Explanation:
I am assuming that you got to go up to Zak as his editor and tell him in his face if he is doing the work correctly. Dont trust me though, cause C also looks plausible
Answer:
Explanation:
Given data
Initial velocity of neutron v₀=1.4×10⁷m/s
Diameter of nucleus d=1×10⁻¹⁴m
Mass of neutron m=1.67×10⁻²⁷kg
The acceleration of neutron is given from equation :
So its magnitude is a=9.81×10²⁷m/s²
To find magnitude of force we use Newtons second law of motion
So
Answer:
Gravitational force = 89.18 x 10^-31 N
Electric force = 2.4 x 10^-17 N
Magnetic force = 7.68 x 10^-17 N
Explanation:
B = 80 micro tesla = 80 x 10^-6 T north
E = 150 N/C downward
v = 6 x 10^6 m/s east
Gravitational force = m g = 9.1 x 10^-31 x 9.8 = 89.18 x 10^-31 N
Electric force = q E = 1.6 x 10^-19 x 150 = 2.4 x 10^-17 N
Magnetic force = q v B Sin 90 = 1.6 x 10^-19 x 6 x 10^6 x 80 x 10^-6
= 7.68 x 10^-17 N
