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sveta [45]
3 years ago
12

Evapotranspiration moves water from _______.

Physics
1 answer:
timama [110]3 years ago
5 0
Earth's land and ocean surface to the atmosphere.
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What is a situation in which friction is helpful?
bagirrra123 [75]
When driving a car on the road
8 0
3 years ago
A car starts to move from rest and covers a distance of 360m in one minute. Calculate the acceleration of the car.
Romashka-Z-Leto [24]
<h2>The acceleration of car is 0.2 ms⁻²</h2>

Explanation:

When the car moves , the distance covered is calculated by the relation

S = u t + \frac{1}{2} a t²

In this question u = 0 , because car was at rest initially

Thus S =  \frac{1}{2} a t²

here S is displacement and a is the acceleration of car

Therefore  360 =  \frac{1}{2} a ( 60 )²

Because time taken is one minute or 60 seconds

Therefore a = \frac{360x2}{3600}

or a = 0.2 m s⁻²

4 0
3 years ago
Which of the following is a physical property?
coldgirl [10]
Flammability, I think!
6 0
3 years ago
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If an object moving at 12 m/s has a kinetic energy of 72 j what is the mass
EleoNora [17]
Simply, apply the formula E = \frac{1}{2}mv^{2} and insert the values of m = mass, v = velocity and E = Energy.
The result will be 72J =  \frac{1}{2}m(12m/s)^{2}, m = 1 kg
5 0
3 years ago
Two Polaroids are aligned so that the initially unpolarized light passing through them is a maximum. At what angle should one of
steposvetlana [31]

To solve this problem it is necessary to apply the law of Malus which describes the change in the Intensity of Light when it crosses a polarized surface.

Mathematically the expression is given as

I = I_0 cos^2\theta

Where,

I_0= Initial Intensity

I = Final Intensity after pass through the polarizer

\theta= Angle between the polarizer and the light

Since it is sought to reduce the intensity by half the relationship between the two intensities will be given as

\frac{I}{I_0} = \frac{1}{2}

Using the Malus Law we have,

I = I_0 cos^2\theta

cos^2\theta = \frac{I}{I_0}

cos^2\theta = \frac{1}{2}

\theta = cos^{-1}(\frac{1}{2})^2

\theta = 75.52\°

Angle with respect to maximum is 90-75.52 = 14.48\°

8 0
2 years ago
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