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Bas_tet [7]
3 years ago
9

PLEASE HELP, evaporation,liquids,solids, and gases involved

Physics
1 answer:
sukhopar [10]3 years ago
5 0
Yes they are involved
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If we decrease the size of a quantum dot that contains an electron, what happens to the energy levels?
Law Incorporation [45]

We will solve this problem using the direct concept related to band gap energy, that is, a band gap is the distance between the valence band of electrons and the conduction band, i. e, the energy range in a solid where no electron states (Electronic state) can exist Mathematically can be described as,

E_n = \frac{h^2n^2}{8mcR^2}

Where,

h = Planck's constant

n = Energy level

mc = Effective mass of the point charge

R = Size of the particle

As you can see the energy is inversely proportional to the size of the particle:

E_n \propto \frac{1}{R^2}

Therefore if the size is decreased, the amount of energy is increased.

6 0
3 years ago
What is one thing magnetism and electricity have in common ?​
Marina86 [1]
Answer: One thing magnetism and electricity have in common is that they are related.
Explanation: Flowing electrons produce a magnetic field, and spinning magnets cause an electric current to flow.
7 0
2 years ago
Name 7 characteristics that are unique to mammals.
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Mammals are endothermic vertebrates
Have hair and fur on the body
Have mammary glands
Four chambered hearts
Have sebaceous (fat secreting glands), sudoriferus (sweat), and scent glands.
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3 0
3 years ago
Read 2 more answers
Consider an electron that is 10-10 m from an alpha particle (9 = 3.2 x 10-19 C). (Enter the magnitudes.) (a) What is the electri
Studentka2010 [4]

Answer:

a)E=2.88*10^{11}N/C

b)E=1.44*10^{11}N/C

c)F=4.61*10^{-8}N

Explanation:

We use the definition of a electric field produced by a point charge:

E=k*q/r^2

<u>a)Electric Field  due to the alpha particle:</u>

E=k*q_{alpha}/r^2=9*10^9*3.2*10^{-19}/(10^{-10})^2=2.88*10^{11}N/C

<u>b)Electric Field  due to electron:</u>

E=k*q_{electron}/r^2=9*10^9*1.6*10^{-19}/(10^{-10})^2=1.44*10^{11}N/C

<u>c)Electric Force on the alpha particle, on the electron:</u>

The alpha particle and electron feel the same force but with opposite direction:

F=k*q_{electron}*q_{alpha}/r^2=9*10^9*1.6*10^{-19}*3.2*10^{-19}/(10^{-10})^2=4.61*10^{-8}N

4 0
3 years ago
Just need the answer
marin [14]

Answer:

1.  1, 2, 4 all show some form of refraction as the bending of a light ray when passing from one media to another.

Explanation:

Number 4 is the most accurate as it also shows some light being reflected and the bending of the refracted light ray in the correct direction for going from a medium of low refractive index (air) into a higher refractive index material (crown glass)

8 0
3 years ago
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