Ok! So, given a quadratic function<span>, </span>y<span> = ax</span>2<span> + bx + c, when "a" is positive, the </span>parabola <span>opens upward and the vertex is the minimum value. On the other hand, if "a" is negative, the graph opens downward and the vertex is the maximum value. Now, let's refer back to our original graph, </span>y<span> = </span><span>x2</span><span>, where "a" is 1.
Hope this helps.</span>
Answer:
Step-by-step explanation:
this is not high school- but uhm
1) KAT
2)TAK
3) SAT
i think thats the answer for the first section..
<h3>
Answer: 
</h3>
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Explanation:
Both legs are the same length, as indicated by the tickmark.
- a =

- b =

- c = x
Use the pythagorean theorem to solve for x

Answer:
m + c = - 4.4
Step-by-step explanation:
Line 1 is given by the equation 5x + 8y = -9, ⇒
........(1) {In slope-intercept form}
If line 2 is perpendicular to the line 1 then the equation of line 2 will be
........ (2), where c is a constant. {Since the product of the slopes of two perpendicular straight line is -1}
Now, the line 2 passes through the point (10,10).
So, from equation (2), we get,

Therefore, the equation of line 2 will be 
This equation is in y = mx + c form where
and c = - 6
Hence, m + c = 1.6 - 6 = - 4.4 (Answer)