Answer:
V = 21145.01 mm³
Step-by-step explanation:
Given that:
The radius of the gumball = 30 mm
The radius of the spherical hollow-core = 28 mm
Consider the radius of the gumball to be 
and the radius of the spherical hollow-core to be 
. Then;
The volume of the gumball can be determined by using the formula of a sphere.
V = 21145.01 mm³
Step-by-step explanation:
This is a probability related question, let the event be E
We know that the likelihood of an event happening is given as
Pr(E)=1
if an event will not occur the probability is
Pr(E)=0
a. This event is impossible: Pr(E)=0
b.This event will occur more often than not, but is not extremely likely:
Pr(E)=0<E>0.5
c.This event is extremely unlikely, but it will occur once in a while in a long sequence of trials:
Pr(E)=0<E<0.5
d.This event will occur for sure: Pr(E)=0
Answer:
Area=190.091 cm^2
Step-by-step explanation:
Area = 1/2(Pi x r^2) one-half because it's a semi-circle
Area=1/2(3.14 x 11^2)
11^2=121 so, Area=1/2(3.14 x 121)
Area=1/2(379.94)
Area=189.97 cm^2
adjustment:
Area=1/2(3.142 x 11^2)
Area=1/2(3.142 x 121)
Area=1/2(380.182)
Area=190.091
Sometimes I’m pretty sure
To do this, simply add the 2 functions-as it says:
(2x+1) + (-3x+4)
2x+1-3x-4
-x-3
Your answer is -x-3
