<h2><em>(</em><em>C</em><em>)</em><em>Ure</em><em>a</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em></h2>
Answer:
x- axis
Explanation:
x- axis is left to right, the run
y- axis is up to down, the rise
Answer:
A
Explanation:
Because it is way more logic
Answer:
a) A beaker filled with 1 liter of deionized water? - water will flow into the bag so its volume will increase. The solution is <u>hypotonic</u>
b) A beaker filled with 1 liter of 10% sucrose solution? - water will flow out of the bag so its volume will reduce. The solution is <u>hypertonic</u>
c) A beaker filled with 1 liter of 2% sucrose solution - the volume of water in the bag will stay the same as the two solutions are in equilibrium. The solution is <u>isotonic</u>
Explanation:
Water moves by osmosis through a semi-permeable membrane. Osmosis describes the simple diffusion of water molecules.
Water molecules will move from a high concentration to a low concentration.
- If the bag of 2% sucrose solution is placed in a beaker of deionized water, the concentration of water in the deionized water is in the beaker higher than in the bag (because the water in the bag contains 2% sucrose). Therefore, the water in the beaker will move from a high concentration outside the bag to a lower concentration inside the bag
- If the bag of 2% sucrose solution is placed in a beaker of 10% sucrose solution, the concentration of water in the bag is higher than in the beaker (because there is more sucrose in the beaker). Therefore, the water in the bag will move from a higher concentration inside the bag to a lower concentration outside the bag.
- When the concentration of water is equal, the movment of water molecules reaches an equilibrium and there will be no change in the volume of water in the bag
I believe it’s an active dye?
