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givi [52]
4 years ago
5

Find the area of the regular polygon below. PLEASE HELP WILL MARK BRAINLIEIST!

Mathematics
2 answers:
mafiozo [28]4 years ago
3 0

Answer:14*8=112

The area is 112

Eddi Din [679]4 years ago
3 0

Answer:

A = 946.37 units^{2}  (approximately)

Step-by-step explanation:

The equation of the area of an octagon is 2a^{2}(1 + \sqrt{2}) where a = side length. In your question, the side length you were given was 14, so plug 14 into the equation in place of a.

So now the equation looks like 2(14^{2})(1 + \sqrt{2})

2(196)(1 + \sqrt{2})

392(1 + \sqrt{2}) now use the distributive property

(392 + 392 \sqrt{2}) = 946.37 units^{2}

Hope this helps!

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PLEASE HELP WILL GIVE BRAINLIEST! What is the following sum? Assume x > or equal to 0 and y is > or equal to 0.
Ira Lisetskai [31]

Answer:

Option (b) is correct.

The sum of given expression  \sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y} is  2xy\sqrt{y}+2xy^2\sqrt{x}

Step-by-step explanation:

Given:Expression \sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}

We have to find the sum of the given expression and choose the correct from the given options.

Consider the given expression  \sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}.

\sqrt{x^2y^3} can be written as \sqrt{x^2y^2y}=xy\sqrt{y}

Also, 2\sqrt{x^3y^4} can be written as 2\sqrt{x^3y^4}=2\sqrt{x^2x(y^2)^2}=2xy^2\sqrt{x}

Now, the given expression becomes,

\sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}

=xy\sqrt{y}+2xy^2\sqrt{x}+xy\sqrt{y}.

Now, adding like term, terms having same variable with same degree.

=2xy\sqrt{y}+2xy^2\sqrt{x}.

Thus, The sum of given expression  \sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y} is  2xy\sqrt{y}+2xy^2\sqrt{x}

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3 years ago
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Step-by-step explanation:

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Answer:

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