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kotykmax [81]
4 years ago
15

PLEASE HELP! Describe the operations used to solve the equation.

D-%5Cfrac%7B2%7D%7B3%7Dx%2B1" id="TexFormula1" title="\frac{5}{6} x-2=-\frac{2}{3}x+1" alt="\frac{5}{6} x-2=-\frac{2}{3}x+1" align="absmiddle" class="latex-formula">

Mathematics
1 answer:
Mama L [17]4 years ago
5 0
The answer to the question

You might be interested in
Question 1 (Essay Worth 10 points)
Anastasy [175]

Answer:

Part A) The system has one solution

Part B) The solution is the point (2.54,3.69)

Step-by-step explanation:

step 1

Find the equation of line A

<em>Find the slope </em>

we have

(2,6) and (5,0)

m=(0-6)/(5-2)=-6/4=-1.5

<em>Find the equation of the line</em>

with the slope m and point (5,0)

y-0=-1.5(x-5)

y=-1.5x+7.5 -----> equation A

step 2

Find the equation of line B

<em>Find the slope </em>

we have

(0,2) and (6,6)

m=(6-2)/(6-0)=4/6=2/3

<em>Find the equation of the line</em>

with the slope m and point (0,2)

y-2=(2/3)(x-0)

y=(2/3)x+2 -----> equation B

step 3

Solve the system of equations

y=-1.5x+7.5 -----> equation A

y=(2/3)x+2 -----> equation B

Solve the system by graphing

Remember that the solution of the system is the intersection point both graphs

The system has one point of intersection

therefore

The system has only one solution

The solution is the point (2.54,3.69)

see the attached figure

8 0
3 years ago
ABC is a right triangle. if AC = 15 and BC = 17, find AB.<br><br> A. 23<br> B. 4<br> C. 64<br> D. 8
victus00 [196]
I hope this helps you



AC^2+AB^2=BC^2


15^2+AB^2=17^2


AB^2=17^2-15^2


AB^2=8^2


AB=8
4 0
4 years ago
Read 2 more answers
Please help me out............
sasho [114]

Answer:y=1

Step-by-step explanation:

6 0
3 years ago
Need help with special right triangles
hjlf

Step-by-step explanation:

For solving this, it's important to know basic trigonometric functions:

sin = opposite side / hypotenuse

cos = adjacent side / hypotenuse

tan = opposite side / adjacent side

It's also important to know that it is necessary to know their values for special right triangles and angles of 30°, 45° and 60°

1. We are given angle if 45° and its adjacent side of 13. We want to know the opposite side (x) and hypotenuse (y). So:

tan = opposite side / adjacent side

tan 45 = x / 13

1 = x / 13

x = 13

Remember that tangent of 45° angle is 1.

We found the opposite side to be also 13.

To find y we can use:

sin = opposite side / hypotenuse

sin 45 = 13 / y

(√2)/2 = 13 / y

y = 13√2

Important to remember, sin 45 and cos 45 are (√2)/2

2. We are given 45° angle and hypotenuse of 30. We need to find opposite side (x) and adjacent side (y).

sin = opposite side / hypotenuse

sin 45 = x / 30

(√2)/2 = x / 30

x = 15√2

Also:

cos = adjacent side / hypotenuse

cos 45 = y / 30

(√2)/2 = y / 30

y = 15√2

We can conclude that in the right triangle, when angle is 45°, opposite and adjacent sides are equal.

3. We are given angle of 60° and adjacent side of 3. We need to find opposite side (y) and hypotenuse (x).

cos = adjacent side / hypotenuse

cos 60° = 3 / x

1/2 = 3 / x

x = 6

Note that cos 60° equals 1/2.

sin = opposite side / hypotenuse

sin 60° = y / 6

(√3)/2 = y / 6

y = 3√3

Note that sin 60° equals (√3)/2.

4. We are given angle of 30° and hypotenuse of 34. We need to find opposite side (y) and adjacent side (x).

sin = opposite side / hypotenuse

sin 30° = y / 34

1/2 = y / 34

y = 17

Note that sin 30° equals to cos 60° equals 1/2.

cos = adjacent side / hypotenuse

cos 30° = x / 34

(√3)/2 = x / 34

x = 17√3

Remember that cos 30° equals to sin 60° which is (√3)/2.

5. We are given an angle of 45° and hypotenuse of 10√2. We need to find the opposite side (y) and adjacent side (x).

sin = opposite side / hypotenuse

sin 45° = y / 10√2

(√2)/2 = y / 10√2

y = 10

To save time, we already said that opposite and adjacent sides are equal in right triangle with 45° angle, so x = y = 10.

6. We are given angle of 60° and opposite side of 25√3. We need to find adjacent side (y) and hypotenuse (x).

sin = opposite side / hypotenuse

sin 60° = 25√3 / x

(√3)/2 = 25√3 / x

x = 50.

tan = opposite side / adjacent side

tan 60° = 25√3 / y

√3 = 25√3 / y

y = 25.

Remember that tangent of 60° angle is √3.

7. We are given angle of 45° and hypotenuse of 2√14. We need to find adjacent side (x) and opposite side (y).

cos = adjacent side / hypotenuse

cos 45° = x / 2√14

(√2)/2 = x / 2√14

x = √28

Again, adjacent and opposite sides are equal in 45° right triangle, so x = y = √28.

8. We are given an angle of 30° and an adjacent side of 24. We need to find the opposite side (y) and hypotenuse (x).

tan = opposite side / adjacent side

tan 30° = y / 24

(√3)/3 = y / 24

y = 8√3

sin = opposite side / hypotenuse

sin 30° = 8√3 / x

1/2 = 8√3 / x

x = 16√3

Note that tan = sin/cos, so tan 30° = sin 30° / cos 30°

tan 30° = 1/2 / (√3)/2 = (√3)/3

I'm showing you this, so you don't have to memorize tan for special angles, you can find it from sin and cos.

9. We are given an angle of 60° and hypotenuse of 22√3. We need to find the opposite side (y) and adjacent side (x).

sin = opposite side / hypotenuse

sin 60° = y / 22√3

(√3)/2 = y / 22√3

y = 33

cos = adjacent side / hypotenuse

cos 60° = x / 22√3

1/2 = x / 22√3

x = 11√3

10. We are given an angle of 30° and the opposite side of √6. We need to find the adjacent side (x) and hypotenuse (y).

sin = opposite side / hypotenuse

sin 30° = √6 / y

1/2 = √6 / y

y = 2√6

tan = opposite side / adjacent side

tan 30° = √6 / x

(√3)/3 = √6 / x

x = √18

11. We are given an angle of 45° and an adjacent side of √10. We need to find the opposite side (x) and hypotenuse (y).

In this triangle opposite and adjacent sides are equal (45° angle), so x = √10

sin = opposite side / hypotenuse

sin 45° = √10 / y

(√2)/2 = √10 / y

y = √20 = 2√5

12. We are given an angle of 60° and the opposite side of 4√21. We need to find the adjacent side (x) and hypotenuse (y).

sin = opposite side / hypotenuse

sin 60° = 4√21 / y

(√3)/2 = 4√21 / y

y = 8√7

tan = opposite side / adjacent side

tan 60° = 4√21 / x

√3 = 4√21 / x

x = 4√7

13. Now things get a little trickier. We are given an angle of 30° and the opposite side of 17. We need to find the adjacent side (x).

Note that, at the moment, we are only dealing with this smaller triangle.

tan = opposite side / adjacent side

tan 30° = 17 / x

(√3)/3 = 17 / x

x = 17√3

Now, note that hypotenuse of the smaller triangle is the same length as the side z (adjacent and opposite side of 45° angle)

With Pythagorean theorem, we can find the hypotenuse of the smaller triangle, which equals to z.

z = √(17^2 + (17√3)^2)

z = 34

And now, finally to find y (hypotenuse of bigger triangle). We are given 45° angle and adjacent side z (34).

cos = adjacent side / hypotenuse

cos 45° = 34 / y

(√2)/2 = 34 / y

y = 34√2

14. Photo added

6 0
3 years ago
CAN YOU READ THIS AND IF YOU CAN HELP ME!!!!! THIS CRAZY ONCE AGAINNNN I NEEDDDD PROFESSIONALLLL!!!!!!!!!!!!!
LUCKY_DIMON [66]
Pretty sure it’s D. hope this helps!
6 0
3 years ago
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