P(not 5) =5/6 and P(5) = 1/6
If the first 5 is rolled on the 5th roll then the first four rolls were not 5
P(5 on fifth roll) = 5/6 x 5/6 x 5/6 x 5/6 x 1/6 = 5^4/6^5 = 625/7776 = 0.080375...
Answer:
Probability of obtaining no more than two defective tubes = 0.816
Step-by-step explanation:
The Probability of obtaining no more than two defective tubes in a randomly selected sample of 15 tubes is obtained using the binomial distribution formula: nCr × p^r × q^(n -r).
Where n is number of samples;
r is maximum number of defective tubes, r ≤ 2;
p is probability of defective tubes = 10% or 0.1
q is probability of non-defective tubes, q = 1 - p
Further explanations and calculations are given in the attachment below:
Answer:
c or d
Step-by-step explanation:
The domain is all real numbers.
(d)The range is y > 0.