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Answer:
<h2><u>question 1</u></h2>use product and sum method
product = -96
sum = -20
numbers needed = ( -24 , 4)
n - 24 = 0
n + 4 = 0
hence <u>n = 24 and n = -4 </u>
<u></u>
<h2><u>Question 2 </u></h2><u /><u />
in the form
=
make use of the formula :
replace values to make 2 equations :
1. = 3.17
2. = -15.2
hence <u>x = 3.17 and x = -15.2</u>
<u />
<h2><u>Question 3 </u></h2><u /><u />
use product and sum method
product = 40
sum = -14
numbers needed = (-10 , -4)
x - 10 = 0
x - 4 = 0
hence<u> x = 10 and x = 4</u>
<u />
<h2><u>Question 4 </u></h2><u /><u />
in the form
this becomes
=
can simplify by 5
=
use product and sum method
product = -5
sum = -4
numbers needed (-5 , 1)
b-5 = 0
b + 1 = 0
hence <u>b = 5 and b = -1</u>
Answer:
The roots (zeros) of the function are:
Step-by-step explanation:
Given the function
substitute f(x) = 0 to determine the zeros of the function
First break the expression x² + 3x - 40 into groups
x² + 3x - 40 = (x² - 5x) + (8x - 40)
Factor out x from x² - 5x: x(x - 5)
Factor out 8 from 8x - 40: 8(x - 5)
Thus, the expression becomes
switch the sides
Factor out common term x - 5
Using the zero factor principle
if ab=0, then a=0 or b=0 (or both a=0 and b=0)
Solve x - 5 = 0
x - 5 = 0
adding 5 to both sides
x - 5 + 5 = 0 + 5
x = 5
solve x + 8 = 0
x + 8 = 0
subtracting 8 from both sides
x + 8 - 8 = 0 - 8
x = -8
Therefore, the roots (zeros) of the function are: