Which expression is equivalent to 1.18 x 0.6

ASAP!: can anyone solve three times the difference of Federico age and 4 increased by 7 is greater than 37 what are possible val

Alexandra [31]

Answer:

Federcio's age possible values are those that are greater than 14 i.e 15, 16, 17 and so on

Step-by-step explanation:

Let Federico's age = x

Three times the difference of Federico’s age, and 4 means:

3(x - 4)

Increased by 7:

3(x - 4) + 7

Is greater than 37:

3(x - 4) + 7 > 37

Solving the inequality:

3x - 12 + 7 > 37

3x - 5 > 37

3x > 37 + 5

3x > 42

x >42/3

x > 14

Federcio's age possible values are those that are greater than 14

7 0

2 years ago

If a/\2+1/a/\2=11, then a+1/a=?

Nadya [2.5K]

Answer:

$\pm \sqrt{13}$

Step-by-step explanation:

$\bigg(a + \frac{1}{a} \bigg)^{2} = {a}^{2} + \frac{1}{ {a}^{2} } + 2 \times a \times \frac{1}{a} \\ \\ \bigg(a + \frac{1}{a} \bigg)^{2} = 11 + 2 \\ \\ \bigg(a + \frac{1}{a} \bigg)^{2} = 13 \\ \\ \bigg(a + \frac{1}{a} \bigg) = \pm \sqrt{13}$

5 0

3 years ago

1. The national mean (μ) IQ score from an IQ test is 100 with a standard deviation (s) of 15. The dean of a college wants to kno

Nat2105 [25]

Answer:

We conclude that the mean IQ of her students is different from the national average.

Step-by-step explanation:

We are given that the national mean (μ) IQ score from an IQ test is 100 with a standard deviation (s) of 15.

The dean of a college want to test whether the mean IQ of her students is different from the national average. For this, she administers IQ tests to her 144 students and calculates a mean score of 113

Let, Null Hypothesis, $H_0$ : $\mu$ = 100 {means that the mean IQ of her students is same as of national average}

Alternate Hypothesis, $H_1$ : $\mu\neq$ 100 {means that the mean IQ of her students is different from the national average}

(a) The test statistics that will be used here is One sample z-test statistics;

T.S. = $\frac{Xbar-\mu}{\frac{s}{\sqrt{n} } }$ ~ N(0,1)

where, Xbar = sample mean score = 113

s = population standard deviation = 15

n = sample of students = 144

So, test statistics = $\frac{113-100}{\frac{15}{\sqrt{144} } }$

= 10.4

Now, at 0.05 significance level, the z table gives critical value of 1.96. Since our test statistics is more than the critical value of z which means our test statistics will fall in the rejection region and we have sufficient evidence to reject our null hypothesis.

Therefore, we conclude that the mean IQ of her students is different from the national average.

3 0

3 years ago

The sign on a clearance rack tells customers the price is 1/2 the lowest marked price. If an item is marked $9.98, how much will

Artyom0805 [142]

Answer:

4.99

Step-by-step explanation:

9.98 divide by 2

3 0

3 years ago

The average number of traffic tickets issued in a city on any given day