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ANTONII [103]
3 years ago
14

Please answer the questions before 12 am

Mathematics
1 answer:
marta [7]3 years ago
7 0

Answer:

8. 4m+2

9. 11m+4

10. 15u or 13u+2u

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Expand and simplify 2(a + 3) + 3(2a - 1)
Svetlanka [38]
2(a+3) + 3(2a-1)
First, let's use the distributive property to expand 2(a+3):
2(a+3) = 2*a + 2*3 = 2a + 6
Let's use the distributive property now to expand 3(2a-1):
3(2a - 1) = 3*2a - 3*1 = 6a - 3

So 2(a+3) + 3(2a-1) = 2a + 6 + 6a - 3
Now you calculate variables between each others, and numbers between each others:
2a + 6 + 6a - 3 = 2a + 6a + 6 - 3 = 8a + 3

So the simplified form of 2(a+3) + 3(2a-1) is 8a + 3.

Hope this Helps! :)
4 0
3 years ago
What is the explicit rule for the sequence?<br><br><br><br> 12,6,0,−6, …
wolverine [178]
Hello!

First you find the common difference in the sequence

6 - 12 = -6
0 - 6 = -6

The common difference is -6

We can now make the equation

-6(n - 1) + 12

we got the 12 because it is the first number in the sequence

Simplify

-6n + 6 + 12

Simplify

18 - 6n

The answer is B) an = 18 - 6n

Hope this helps!
7 0
3 years ago
What is the 9th term of (2x+3)^10<br><br><br> PLEASEEEEEEE ANSWERRRRR
Bond [772]

Answer:

1.668x10^13

Step-by-step explanation:

5 0
3 years ago
A call center data set shows that in a sample of 30 ​individuals, 11 had prior call center experience. If we assume that the pro
ira [324]

Answer:

P(X > 5) = 0.1164 to 4 d.p.

The parameters are defined in the explanation.

Step-by-step explanation:

This is a binomial distribution problem

Binomial distribution function is represented by

P(X = x) = ⁿCₓ pˣ qⁿ⁻ˣ

n = total number of sample spaces = number of potential hires = 10

x = Number of successes required = number of potential hires that have prior call centre experience = more than half; that is, x > 5

p = probability of success = probability that any potential hire will have experience = (11/30) = 0.367

q = probability of failure = probability that any potential hire will NOT have experience = 1 - p = 1 - 0.367 = 0.633

P(X > 5) = P(X=6) + P(X=7) + P(X=8) + P(X=9) + P(X=10)

Inserting the parameters and computing the probabilities for each of those values of X,

P(X > 5) = 0.11641775484 = 0.1164 to 4 d.p.

Hope this Helps!!!

4 0
2 years ago
Hello could I get help ?
mr_godi [17]

Answer:

can't prove a nt with info given

6 0
2 years ago
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