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FrozenT [24]
3 years ago
9

Frances has no money in her checking account. she writes 3 checks for $35 each. the bank imposes $15 penalty because she has ove

rdrawn her account. how much money is in her account now?
Mathematics
2 answers:
Marizza181 [45]3 years ago
8 0
0-35=-35-(-35)=-70-(-35)=-105-(-15)=-120. so -120 would be your answer. hope this helped. 
Gwar [14]3 years ago
8 0

Answer:

-\$120

Step-by-step explanation:

We have been given that Frances has no money in her checking account. She writes 3 checks for $35 each.

The amount drawn from the account would be 3\times \$35=\$105.

The amount after imposing $15 penalty would be \$105+\$15=\$120.

Since Frances has no money in her checking account initially, so she will have a debt of -\$120.

Therefore, she has -\$120 in her account now.

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18=3(1+12 x)-5(10x+11)
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18=3+36x-50x-55

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6 0
3 years ago
Each carton 12 eggs. There are 2 full cartons in the refrigerator. Margot uses 3 eggs to make a quiche. How many eggs are left.
3241004551 [841]

Answer:

Answer: There are 21 eggs left.

Step-by-step explanation:

One carton has 12 eggs.

2 cartons are two times one carton, so two cartons have 2 times 12 eggs.

2 * 12 = 24

There are 24 eggs in two cartons.

Margot uses 3 eggs. We subtract 3 eggs from 24 eggs.

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6 0
3 years ago
How do you use theorems about triangles to solve problems??? ​
bazaltina [42]

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Explanation:

Theorems about triangles identify relationships that can be used to formulate equations that can be used in the problem-solving process.

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8 0
2 years ago
According to the article "Characterizing the Severity and Risk of Drought in the Poudre River, Colorado" (J. of Water Res. Plann
mihalych1998 [28]

Answer:

(a) P (Y = 3) = 0.0844, P (Y ≤ 3) = 0.8780

(b) The probability that the length of a drought exceeds its mean value by at least one standard deviation is 0.2064.

Step-by-step explanation:

The random variable <em>Y</em> is defined as the number of consecutive time intervals in which the water supply remains below a critical value <em>y₀</em>.

The random variable <em>Y</em> follows a Geometric distribution with parameter <em>p</em> = 0.409<em>.</em>

The probability mass function of a Geometric distribution is:

P(Y=y)=(1-p)^{y}p;\ y=0,12...

(a)

Compute the probability that a drought lasts exactly 3 intervals as follows:

P(Y=3)=(1-0.409)^{3}\times 0.409=0.0844279\approx0.0844

Thus, the probability that a drought lasts exactly 3 intervals is 0.0844.

Compute the probability that a drought lasts at most 3 intervals as follows:

P (Y ≤ 3) =  P (Y = 0) + P (Y = 1) + P (Y = 2) + P (Y = 3)

              =(1-0.409)^{0}\times 0.409+(1-0.409)^{1}\times 0.409+(1-0.409)^{2}\times 0.409\\+(1-0.409)^{3}\times 0.409\\=0.409+0.2417+0.1429+0.0844\\=0.8780

Thus, the probability that a drought lasts at most 3 intervals is 0.8780.

(b)

Compute the mean of the random variable <em>Y</em> as follows:

\mu=\frac{1-p}{p}=\frac{1-0.409}{0.409}=1.445

Compute the standard deviation of the random variable <em>Y</em> as follows:

\sigma=\sqrt{\frac{1-p}{p^{2}}}=\sqrt{\frac{1-0.409}{(0.409)^{2}}}=1.88

The probability that the length of a drought exceeds its mean value by at least one standard deviation is:

P (Y ≥ μ + σ) = P (Y ≥ 1.445 + 1.88)

                    = P (Y ≥ 3.325)

                    = P (Y ≥ 3)

                    = 1 - P (Y < 3)

                    = 1 - P (X = 0) - P (X = 1) - P (X = 2)

                    =1-[(1-0.409)^{0}\times 0.409+(1-0.409)^{1}\times 0.409\\+(1-0.409)^{2}\times 0.409]\\=1-[0.409+0.2417+0.1429]\\=0.2064

Thus, the probability that the length of a drought exceeds its mean value by at least one standard deviation is 0.2064.

6 0
3 years ago
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