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Naddika [18.5K]
3 years ago
13

A student club set a goal of donating 50 blankets to a local shelter. Two classes have participated so far. Ms. Carter’s class g

athered 18 blankets and Mr. Moriarti’s class gathered 23 blankets. How many more blankets are needed to reach the goal of 50 blankets
What type of problem is this? How can you tell?

a part-whole problem because Ms. Carter’s class only gathered part of the number of blankets Mr. Moriarti’s class gathered

a part-whole problem because the unknown number of blankets that are still needed is part of the whole goal of 50 blankets

a comparison problem because the number of blankets gathered is compared to the number of blankets still needed

a comparison problem because the number of blankets Ms. Carter’s class gathered is compared to the number of blankets Mr. Moriarti’s class gathered
Mathematics
1 answer:
oee [108]3 years ago
8 0
The correct answer is that this is a part whole problem because the unknown number of blankets that are still needed is part of the whole goal of 50 blankets.
the whole value should be 50 blankets. Part of these blankets have already been collected, thats (18 +23) 41 blankets.
we have been given the whole that's 50 and we have been given the part thats 41 in total. we still have to find the other part that should be included to make the whole number of blankets. We can find the unknown number by subtracting the part given (41) from the whole (50) and the unknown is then 9 blankets.
Therefore this is a part whole problem to find out the missing part.

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Tina is finding the quotient of. Is she correct? If not, what changes should be made?
Mice21 [21]

For this case, we must find the quotient of

(15x ^ 3 + 12x ^ 2-9x) divided by3x, to verify if Tina was correct.

So:

\frac {15x ^ 3 + 12x ^ 2-9x} {3x} =\\\frac {15x ^ 3} {3x} + \frac {12x ^ 2} {3x} - \frac {9x} {3x} =\\5x ^ 2 + 4x-3

So, Tina was wrong, she had to divide by 3x.

Answer:

Option B


5 0
3 years ago
Find the 15th term of this arithmetic sequence for 20,26,32,38,44
olga2289 [7]

Answer:

104

Step-by-step explanation:

There are two ways to do it, though we need to know how it is affected.

20+6=26

26+6=32

32+6=38

38+6=44

Thus, you are adding 6 for each term.

1. You do it manually...(yes.)

I'll number it one by one

1.20

2.26

3.32

4.38

5.44

6.50

7.56

8.62

9.68

10.74

11.80

12.86

13.92

14.98

15.104

The 15th term is 104.

2. This method is easier. As shown above, there is a pattern. We can apply it using this formula:
20+6(n-1)

You can get this formula from the facts that:
-you start off with an additional added 8

-you add 6 every time

-if we do it 6n then it would be incorrect, with an extra 6 for each

-the formula is correct; you can test it for terms 2,3,4,5 like this:

20+6=26

20+2x6=32

20+3x6=38

20+4x6=44

To find the 15th term, you can:

20+14x6=20+84=104.

5 0
2 years ago
A(-2,3)
Anika [276]

Answer:

The perimeter of triangle is 19.8 units

Step-by-step explanation:

we know that

The perimeter of triangle ABC is

P=AB+BC+AC

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

step 1

Find the distance AB

we have

A(-2,3),B(3,0)

substitute in the formula

d=\sqrt{(0-3)^{2}+(3+2)^{2}}

d=\sqrt{(-3)^{2}+(5)^{2}}

d_A_B=\sqrt{34}\ units

step 2

Find the distance BC

we have

B(3,0),C (-4,-3)

substitute in the formula

d=\sqrt{(-3-0)^{2}+(-4-3)^{2}}

d=\sqrt{(-3)^{2}+(-7)^{2}}

d_B_C=\sqrt{58}\ units

step 3

Find the distance AC

we have

A(-2,3),C (-4,-3)

substitute in the formula

d=\sqrt{(-3-3)^{2}+(-4+2)^{2}}

d=\sqrt{(-6)^{2}+(-2)^{2}}

d_A_C=\sqrt{40}\ units

step 4

Find the perimeter

P=AB+BC+AC

substitute the values

P=\sqrt{34}+\sqrt{58}+\sqrt{40}

P=19.8\ units

4 0
3 years ago
13. A quadratic function passes through the points (0,5), (2,3), and (3,5). Which
muminat

Answer:

B

Step-by-step explanation:

5 0
3 years ago
Solve:<br> 0.03g - (2g + 3) = 1.8
wel

Answer:

-2.43655

Step-by-step explanation:

3 0
3 years ago
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