Answer:
Calculate the volume (in mL) of the 1.356 M stock NaOH solution needed to prepare 250.0 mL ... Glucose (molar mass=180.16 g/mol) is a simple, soluble sugar ... g of glucose in enough water to make 500.0 mL of solution. • Step 2: Transfer 18.6 mL of glucose
50,290,000 KM
50,290,000*1000= 5290000000 meters
In order to purify ammonia to high purity, two basic methods are used. The older one consists in passing gaseous ammonia containing 80 ppm of impurities under atmospheric pressure through liquid ammonia with dissolved metallic sodium.
Answer:
a. 473mL.
b. 79.38kg
c. 24.47lb of fat
d. 42.5g of N.
Explanation:
a. A qt is equal to 946mL. 0.500qt are:
0.500qt * (946mL / 1qt) = 473mL
b. 1lb is equal to 0.4536kg, 175lb are:
175lb *(0.4536kg / 1lb) = 79.38kg
c. The fat in kg of the athlete is:
74kg * 15% = 11.1kg of fat. In pounds:
11.1kg * (1lb / 0.4536kg) = 24.47lb of fat
d. The mass of nitrogen in the fertilizer is:
10.0oz * 15% = 1.5oz of N
1 oz is equal to 28.35g. 1.5oz are:
1.5oz * (28.35g / 1oz) = 42.5g of N
Answer: It’s called a alpha particle
Explanation:
