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3 years ago

A physician may need to increase a patient's prescribed dosage if he or she has developed what?

1 answer:

5 0

The answer to this question would be: resistance

When a patient developing a resistance to a certain drug, the same amount of doses will not exert the same effect as before. The effect will be lower, thus the doctor will need to increase the dose to increase the effect

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carol accidentally dropped a container of salt and sodium chloride, into a container of a dark grey metal. carol is pretty sure

o-na [289]

Explanation:

The best way to separate the mixture is by using a bar magnet. We explore the magnetic property of the iron fillings in the mixture to separate it out.

The mixture is spread out thinly on a flat surface.
A bar magnet is hovered above the spread of the mixture
The magnet attracts the iron fillings to itself
This will leave the salt behind in the mixture.

4 0

3 years ago

Eview Questions

otez555 [7]

Answer:

Qualitative: Physical observations (the sky is blue, the water is boiling, etc.)

Quantitative: Numberical observations (density= 1 g/ml, volume= 14 ft^3, etc.)

Explanation:

The way to remember it is quaLitative is qualities of the object. QuaNtitative is quantities of the object.

5 0

3 years ago

2C4H10+13O2-->8CO2+10H2O Using the predicted and balanced equation, How many Liters of CO2 can be produced from 150 grams of

Anna11 [10]

Answer: 233 L of $CO_2$ will be produced from 150 grams of $C_4H_{10}$

Explanation:

To calculate the moles :

$\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}$ $\text{Moles of} C_4H_{10}=\frac{150g}{58g/mol}=2.59moles$

The balanced chemical equation is:

$2C_4H_{10}+13O_2(g)\rightarrow 8CO_2+10H_2O$

According to stoichiometry :

2 moles of $C_4H_{10}$ produce = 8 moles of $CO_2$

Thus 2.59 moles of $C_4H_{10}$ will produce= $\frac{8}{2}\times 2.59=10.4moles$ of $CO_2$

Volume of $CO_2=moles\times {\text {Molar volume}}=10.4moles\times 22.4mol/L=233L$

Thus 233 L of $CO_2$ will be produced from 150 grams of $C_4H_{10}$

8 0

3 years ago

A person applies a force of 200 N over 1.5 m to a jack. The jack exerts a 1000-N force on a car a distance of 0.02 m. What is th

xz_007 [3.2K]

Answer:

The efficiency rating of the jack is 0.067.

Explanation:

We have, a person applies a force of 200 N over 1.5 m to a jack. The jack exerts a 1000-N force on a car a distance of 0.02 m.

It is required to find the the efficiency rating of the jack. It is equal to the ratio of output work to the ratio of input work. So,

$\eta=\dfrac{1000\times 0.02}{200\times 1.5}\\\\\eta=0.067$

Thus, the efficiency rating of the jack is 0.067.

6 0

3 years ago

Two objects of equal mass have a force of gravity of 6 N between them. Imagine the mass of one is cut in half and the other stay

Alenkasestr [34]

Answer:

F' = 3 N

Explanation:

Given that,

Two objects of equal mass have a force of gravity of 6 N between them.

If the mass of one is cut in half and the other stays the same such that,

m₁' = m₁ and m₂' = (m₂/2)

We need to find the new force. The gravitational force between two objects is given by :

$F=G\dfrac{m_1m_2}{r^2}$

We have, F = 6 N

New force,

$F'=G\dfrac{m_1'm_2'}{r^2}\\\\F'=\dfrac{Gm_1\times \dfrac{m_1}{2}}{r^2}\\\\=\dfrac{1}{2}\times \dfrac{Gm_1m_2}{r^2}\\\\F'=\dfrac{F}{2}\\\\F'=\dfrac{6}{2}\\\\F'=3\ N$

So, the new force becomes 3 N.

3 0

3 years ago