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LenKa [72]
3 years ago
6

A sample of hydrogen gas in a flask of volume 25.0 mL has a pressure of 487.3 mm Hg at 20.5 o C. This sample is transferred into

a flask of unknown volume. The pressure is measured to be 99.7 mm Hg and the temperature is raised to 24.5 o C in the new flask. What is the volume of the new flask
Chemistry
1 answer:
Veseljchak [2.6K]3 years ago
6 0

Answer:

124 mL is the volume for the new flask

Explanation:

We can apply the Ideal Gases law for both situations where the volume of Hydrogen remains constant.

The formula is P . V = n . R . T

We despise n because, as we said the moles remain constant and R, because it is a value that never changes.

(P₁ . V₁) / T₁ = (P₂ . V₂) / T₂

Let's do unit's conversion:

20°C + 273 = 293K         487.3 mmHg . 1 atm / 760mmHg = 0.641 atm

24.5°C + 273 = 297.5K    99.7 mmHg. 1 atm / 760mmHg = 0.131 atm

25mL . 1L / 1000mL = 0.025L

We replace data:

(0.641 atm .  0.025L) / 293K = (0.131 atm . V₂) / 297.5K

[(0.641 atm .  0.025L) / 293K]  . 297.5K = 0.131 atm . V₂

0.0163 atm.L = 0.131 atm . V₂

V₂ = 0.0163 atm.L / 0.131 atm → 0.124L

We convert volume to mL → 0.124 L . 1000mL / 1L  = 124 mL

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posledela

The question is incomplete, here is the complete question:

When silver nitrate reacts with copper, copper(II) nitrate and silver are produced. The balanced equation for this reaction is:

2AgNO_3+Cu\rightarrow Cu(NO_3)_2+2Ag

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<u>Explanation:</u>

We are given:

Moles of silver nitrate = 6 moles

For the given chemical reaction:

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So, 6 moles of silver nitrate will react with = \frac{1}{2}\times 6=3mol of copper metal

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By Stoichiometry of the reaction:

2 moles of silver nitrate produces 1 mole of copper(II) nitrate

So, 6 moles of silver nitrate will produce = \frac{1}{2}\times 6=3mol of copper(II) nitrate

Moles of copper(II) nitrate produced = 3 moles

  • <u>For silver metal:</u>

By Stoichiometry of the reaction:

2 moles of silver nitrate produces 2 moles of silver metal

So, 6 moles of silver nitrate will produce = \frac{2}{2}\times 6=6mol of silver metal

Moles of silver metal produced = 3 moles

Hence, the amount of copper metal reacted is 3 moles, amount of copper (II) nitrate produced is 3 moles and amount of silver metal produced is 6 moles.

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