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Alisiya [41]
3 years ago
10

Ned help on this plz hurry

Mathematics
1 answer:
svp [43]3 years ago
5 0

Answer:

Option A will be correct.

Step-by-step explanation:

Given that polygon ABCD and polygon JKLM are similar.

Therefore, the corresponding sides of the two similar polygons will be in the same ratio.

Hence, \frac{AB}{JK} = \frac{BC}{KL} = \frac{CD}{LM} = \frac{DA}{MJ}

Hence, we can write \frac{3}{x} = \frac{6}{59}

⇒ x = \frac{59}{2} = 29.5 {Since given that CD = 3, DA = 6, LM = x and MJ = 59}

Therefore, option A will be correct. ( Answer )

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4x + 3y = −6<br> 6x + 3y = −6
Lena [83]

Answer:

no solution

Step-by-step explanation:

If first equation is divided by 2 and the second equation is divided by 3, we get two equations 2x+y=3 and 2x+y= 4. These two lines are parallel and there cannot be any solution to the system

8 0
3 years ago
ILL GIVE U 20 POINTS AND BRAINLIEST, pls hurry!
serious [3.7K]

Answer:

(1/2,5)

Step-by-step explanation:

4 0
3 years ago
A hot dog costs $1 at the ballpark. Which equation shows the total cost, C, of n hot dogs?
pochemuha
C=1n is the answer because the cost of hotdogs equals the price times the number of hotdogs
5 0
1 year ago
Read 2 more answers
How many trucks carried only late variety?
murzikaleks [220]

9514 1404 393

Answer:

  • late only: 15
  • extra-late only: 24
  • one type: 43
  • total trucks: 105

Step-by-step explanation:

It works well when making a Venn diagram to start in the middle (6 carried all three), then work out.

For example, if 10 carried early and extra-late, then only 10-6 = 4 of those trucks carried just early and extra-late.

Similarly, if 30 carried early and late, and 4 more carried only early and extra-late, then 38-30-4 = 4 carried only early. In the attached, the "only" numbers for a single type are circled, to differentiate them from the "total" numbers for that type.

__

a) 15 trucks carried only late

b) 24 trucks carried only extra late

c) 4+15+24 = 43 trucks carried only one type

d) 38+67+56 -30-28-10 +6 +6 = 105 trucks in all went out

8 0
2 years ago
∠ABC and ∠CBD are complementary angles. m∠ABC = (3x + 6)º and m∠CBD = (4x – 14)º.
yuradex [85]
You need use your strategies multiplie it than simplify to k and than move it to E tens
4 0
2 years ago
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