Answer:
Any [a,b] that does NOT include the x-value 3 in it.
Either an [a,b] entirely to the left of 3, or
an [a,b] entirely to the right of 3
Step-by-step explanation:
The intermediate value theorem requires for the function for which the intermediate value is calculated, to be continuous in a closed interval [a,b]. Therefore, for the graph of the function shown in your problem, the intermediate value theorem will apply as long as the interval [a,b] does NOT contain "3", which is the x-value where the function shows a discontinuity.
Then any [a,b] entirely to the left of 3 (that is any [a,b] where b < 3; or on the other hand any [a,b] completely to the right of 3 (that is any [a,b} where a > 3, will be fine for the intermediate value theorem to apply.
Answer:
4 days a week
Step-by-step explanation:
2+1=3
3+1/2+12=4
Answer:
y = 5/2x - 5
Step-by-step explanation:
You have to rearrange the equation so that it is equal to y.
5x - 2y = 10
(5x - 2y) - 5x = -5x + 10
-2y = -5x + 10
(-2y)/-2 = (-5x)/-2 + (10)/-2
y = 5/2x - 5
5x+ (5)15
or
5(x+15)
I hope this helps
Since the basis is from year 1 to year 2, calculate first for the difference of their percentages. That would be:
Difference = year 2 - year 1
Difference = 2.32% - 1.1% = 1.22%
We apply this same value of percentage increase from year 2 to year. Thus, the percentage for year 3 is:
% Year 3 = % Year 2 + percentage increase
% Year 3 = 2.32% + 1.22%
% Year 3 = 3.54%
