Answer:
The density of the bar of gold is 19.32 grams per cubic centimeter .
Step-by-step explanation:
Formula
As given
A bar of gold has a volume of 722 cubic centimeters and weighs 13.949 kilograms.
As 1 kilogram = 1000 gram
Than convert 13.949 kilograms into grams.
13.949 kilograms = 13.949 × 1000 grams
= 13949 grams
Mass = 13949 grams
Volume = 722 cubic centimeter
As put in the formula
Density = 19.32 grams per cubic centimeter (Approx)
Therefore the density of the bar of gold is 19.32 grams per cubic centimeter .
Answer:
−20x − 8
Step-by-step explanation:
Answer:
700
Step-by-step explanation:
The value of the number is 80,000
Answer:
d = 1.46 m
Step-by-step explanation:
We'll begin by obtaining the relationship between the force (F) and the distance (d). This can be obtained as follow:
From the question given above,
F is inversely proportional to square of d. This can be written as:
F ∝ 1/d²
F = K/d²
Cross multiply
K = Fd²
But:
Force (F) = 0.006 N
Distance (d) = 4 m
Constant (K) =?
K = Fd²
K = 0.006 × 4²
K = 0.006 × 16
K = 0.096 Nm²
Therefore, the relationship between the force (F) and the distance (d) is:
F = K/d²
F = 0.096 / d²
Finally, we shall determine the distance when the force is 0.045 N. This can be obtained as follow:
Force (F) = 0.045 N
Constant (K) = 0.096 Nm²
Distance (d) =?
F = K/d²
0.045 = 0.096 / d²
Cross multiply
0.045 × d² = 0.096
Divide both side by 0.045
d² = 0.096 / 0.045
Take the square root of both side.
d = √(0.096 / 0.045)
d = 1.46 m.
