Answer:
CO₃²⁻(aq) + 2H⁺(aq) → CO₂ (g) + H₂O (l)
Explanation:
The balanced reaction between Na2CO3 and HCl is given as;
Na₂CO₃ (aq) + 2 HCl (aq) → 2 NaCl (aq) + CO₂ (g) + H₂O (l)
The next step is o express the species as ions.
The complete ionic equation for the above reaction would be;
2Na⁺(aq) + CO₃²⁻(aq) + 2H⁺(aq) + 2Cl⁻(aq) → Na⁺(aq) + Cl⁻(aq) + CO₂ (g) + H₂O (l)
The next step is to cancel out the spectator ion ions; that is the ions that appear in both the reactant and product side unchanged.
The spectator ions are; Na⁺ and Cl⁻
The net ionic equation is given as;
CO₃²⁻(aq) + 2H⁺(aq) → CO₂ (g) + H₂O (l)
Answer:
B. Two electrons
Explanation:
Since the S orbital is closest to the nucleus and it only has one orbital, it can only hold 2 electrons
As can be seen in the attached image, α-pyrone has a highly electrophilic carbon atom, since it is attached to two oxygen atoms that are electronegative and subtract electrical charge from the carbon, leaving it with a <u>positive partial charge</u>. By virtue of the above, <u>the bromine atoms, which have an important electron density that makes them good nucleophiles, will be attracted to the aforementioned carbon due to their positive charge</u>, thus favoring the substitution product to a greater extent than that of addition.
The characteristic bright-line spectrum of an element is produced when its electrons return to lower energy levels To be in the ground state all electrons must be in their lowest energy state; all excited atoms must lose energy. The lost energy appears in the form of light. Hope this helped :)
" if a compound is an acid or a base, but NOT one of the strong acids or bases, then it MUST be a weak electrolyte. Strong electrolytes – ionic or molecular compounds that ionize completely in solution. Weak electrolytes– molecular compounds that are partially ionized in solution."
