Answer:
21.12°C
Explanation:
Q = m×c×∆T
Where;
m= mass
c= specific heat capacity
∆T = change in temperature
Qwater = - (Qtungsten)
Note that; the initial temperature of tungsten = final temperature of water
For Water, m= 40.37g, initial temperature=21.3°C, c= 4.184J/g°C
For tungsten, m= 60g, final temperature=24.9°C, c= 0.132J/g°C
(m×c×∆T)water = - (m×c×∆T)tungsten
40.37 × 4.184 × (T-21.3) = - {60 × 0.132 × (24.9-T)}
168.91 (T-21.3) = - { 7.92 (24.9-T)}
168.91T - 3597.8 = - (197.21 - 7.92T)
168.91T - 3597.8 = - 197.21 + 7.92T
168.91T - 7.92T = - 197.21 + 3597.8
160.99T = 3400.59
T = 3400.59/160.99
T = 21.12°C
Therefore, the initial temperature, in °C of tungsten cylinder is 21.12°C
