"The boron-nitrogen interaction in the studied molecules shows some similarities with the N→B bond in the H3N-BH3 molecule, formally understood as covalent-dative. ... The results show that all the studied BN bonds are triple, since three two-center orbitals have been obtained."
"Formation of a dative bond or coordinate bond between ammonia and boron trifluoride. When the nitrogen donates a pair of electrons to share with the boron, the boron gains an octet. ... In addition, a pair of non-bonding electrons becomes bonding; they are delocalized over two atoms and become lower in energy."
Answer: THe anwser for the first one is Carbon monoxide, Cupric selenide, iron or sulfide, lead dioxide
Explanation: i took these in science ur welcome
If each atom of element D has 3 mass units and each atom of element E has 5 mass units, a molecule composed ..... The electron configuration for the carbon atom (c) is 1s2 2s2 2p2.
Answer:
D?
Explanation:
I think D hmm is the answer if I am wrong pls anyone or someone type the right answer but for me is d
Zn + I2 = ZnI2
Percentage yield = actual yield / theoretical yield * 100
Actual yield of ZnI2 = 515.6g
Mole of zinc reacted = 125 / 65.4 = 1.91 mol
for every 1 mole of zinc will form 1 mole of ZnI2
Mole of ZnI2 formed = 1.91 * 1 = 1.91 mol
Theoretical yield of ZnI2 = 1.91 * (65.4 + 126.9*2) = 609.672 g
515.6 / 609.672 * 100 = 84.6%
