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vlabodo [156]
3 years ago
9

What is the maximum amount of kcl that can dissolve in 200 g of water? (the solubility of kcl is 34 g/100 g h?

Chemistry
1 answer:
posledela3 years ago
4 0
The answer is 68 g
hope this helps!!
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In an experiment, Ann mixes concentrated sulfuric acid with water in a reaction test tube. The walls of the test tube turn hot.W
vladimir2022 [97]
B) Exothermic
The reaction released heat energy to its surrounding, thus, it was exothermic.
"exo" is to expel or put outside
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8 0
3 years ago
Read 2 more answers
4.80 qt is the same as how many mL?
Marina CMI [18]

Answer:

onverted

Conversion factor: 946.352946

1) mL = Quart * 946.352946

2) mL = 4.8 * 946.352946

3) mL = 4542.4941

3 0
3 years ago
PLS HELP IF YOU WANT A BRAINLIEST BEST ANSWER CHOICE, GETS A BRAINLIEST
Natalija [7]

Answer:

It would be 25% because each equals 25%.

Explanation:

There is 4 "shapes" each can equal 25 because 25+25+25+25=100.

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3 years ago
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Calculate the amount of heat needed to boil 64.7 g of benzene (C6H6), beginning from a temperature of 41.9 C . Round your answer
JulsSmile [24]

Answer: The amount of heat needed is = 4.3kJ

Explanation:

Amount of heat H = M × C × ΔT

M= mass of benzene = 64.7g

C= specific heat capacity = 1.74J/gK

ΔT = T2-T1

Where T1 is initai temperature = 41.9C

T2 is the final temperature( boiling point of benzene) = 80.1C

H= 64.7×1.74×80.7

H= 4300J

H=4.3kJ

Therefore, the amount of heat needed is 4.3kJ

8 0
2 years ago
A 55-mL solution of H2SO4 is completely neutralized by 46 mL of 1.0M NaOH. What is the concentration of the H2SO4∆H2SO4(aq) +2Na
slega [8]
H₂SO₄ + 2NaOH = Na₂SO₄ + 2H₂O

v(NaOH)=46 ml=0.046 l
c(NaOH)=1.0 mol/l
v(H₂SO₄)=55 ml=0.055 l

n(NaOH)=v(NaOH)*c(NaOH)

n(H₂SO₄)=0.5n(NaOH)

c(H₂SO₄)=n(H₂SO₄)/v(H₂SO₄)=0.5*v(NaOH)*c(NaOH)/v(H₂SO₄)

c(H₂SO₄)=0.5*0.046*1.0/0.055=0.418 mol/l

The concentration of the H₂SO₄ is 0.418M.

4 0
3 years ago
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