The solution would be like this for this specific problem:
sin(θ°) = √(2)/2
θ° = 360°n + sin⁻¹(√(2)/2) and θ° = 360°n + 180° −
sin⁻¹(√(2)/2)
θ° = 360°n + 45° and θ° = 360°n + 135° where n∈ℤ
360°*0 + 45° = 45°
360°*0 + 135° = 135°
360°*1 + 45° = 405°
<span>sin(225°) = -√(2)/2
</span>225 has an angle where sin theta= -(sqrt2)/2 therefore, the value of theta
cannot be 225 degrees.
It’s A i did the test myself..
Answer:
Final answer is approx x=0.16.
Step-by-step explanation:
Given equation is 
Now we need to solve equation
and round to the nearest hundredth.











Round to the nearest hundredth.
Hence final answer is approx x=0.16.
Answer:
It has two terms.
Step-by-step explanation: