Answer:
b) v
Explanation:
the distance between pole and position of image can denoted by <u>v</u>
To solve this problem it is necessary to apply the concepts related to the continuity of fluids in a pipeline and apply Bernoulli's balance on the given speeds.
Our values are given as


From the continuity equations in pipes we have to

Where,
= Cross sectional Area at each section
= Flow Velocity at each section
Then replacing we have,



From Bernoulli equation we have that the change in the pressure is

![7.3*10^3 = \frac{1}{2} (1000)([ \frac{(1.25*10^{-2})^2 }{0.6*10^{-2})^2} v_1 ]^2-v_1^2)](https://tex.z-dn.net/?f=7.3%2A10%5E3%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20%281000%29%28%5B%20%5Cfrac%7B%281.25%2A10%5E%7B-2%7D%29%5E2%20%7D%7B0.6%2A10%5E%7B-2%7D%29%5E2%7D%20v_1%20%5D%5E2-v_1%5E2%29)


Therefore the speed of flow in the first tube is 0.9m/s
Answer:
Ос.
The spacing between particles increases.
Heat causes greater particle activity, and the particles
are farther apart.
Answer:
$55.6
Explanation:
sorry sorry sorry sorry sorry
Answer: It will amount to 11p after 20 years.
Explanation:
Formula :
Simple interest = Principal x rate x Time (i)
Amount = Principal + Interest
Amount = Principal + Principal x rate x Time
Amount = Principal (1+ rate x Time) (ii)
Given: Principal = p
After 1 year , amount = 1.5p
After 3 years , amount = 2.5p
From (ii)

Amount after 20 years = p(1+ 0.5 x 20) = p(1+10)=11p
It will amount to 11p after 20 years.