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nikdorinn [45]
3 years ago
14

A wheel of mass 60.0 kg is pushed with a net force of 26.4 N. Find acceleration.

Physics
1 answer:
worty [1.4K]3 years ago
4 0

F= ma; a= F/m

a = 26.4 N/60 kg= 0.44 m/s^2

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How is mercury barometer constructed ?<br>​
olganol [36]

Answer:

A  mercury barometer is a device use to measure stomspheric pressure and is constructed as following:

  • A mercury barometer requires a tube which has one close end, and one open end.
  • Tube is placed upside down in a beaker in such a way so that one end open in the beaker and the other remain outside of the beaker.
  • The barometric liquid (mercury) is then filled in the tube by pouring mercury liquid in the beaker.

The position of tube creates vacuum between the closed end of the tube and liquid surface and the Mercury has high density that is why used as the liquid to measure pressure.

4 0
3 years ago
What do you call the curved upper surface of the water that comely appears when using a graduated cylinder
algol [13]
The curved surface of water is called the meniscus
6 0
3 years ago
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What is the frequency of microwaves of wavelength 3 cm?
tiny-mole [99]

Answer:

10 GHz

Explanation:

Applying,

v = λf.................... Equation 1

Where v = speed of microwave, λ = wavelength, f = frequency.

make f the subject of the equation

f = v/λ................ Equation 2

Note: Microwave is an electromagnetic wave, and all electromagnetic wave have the same speed, which is 3×10⁸ m/s

From the question,

Given: λ = 3 cm = 0.03 m

Constant; v = 3×10⁸ m/s

Substitute these values into equation 2

f = 3×10⁸/(0.03)

f = 10¹⁰ Hz

f = (10¹⁰/10⁹) GHz

f = 10 GHz

4 0
2 years ago
A vibrating pendulum makes 20 complete vibrations in 12.2 seconds. Determine the vibrational period of the pendulum, along with
Hitman42 [59]

Answer:

And the same can be said of a pendulum vibrating about a fixed position or of a guitar ... along the time axis, it is possible to determine the time for one complete cycle. ... It takes 2.3 seconds to complete the first full cycle of vibration. ... Since the standard metric unit of time is the second, frequency has units of cycles/second.

Explanation:

Plz mark brainliest im only 12. and i have never been marked brainliest.

4 0
2 years ago
Determine the gravitational potential energy, in kJ, of 3 m3 of liquid water at an elevation of 40 m above the surface of Earth.
melomori [17]

Explanation:

We will calculate the gravitational potential energy as follows.

                 P.E_{1} = mgz_{1}

       P.E_{1} = (\rho V)gz_{1}    

                    = 1000 kg/m^{3} \times 3 m^{3} \times 9.7 \times 40 m

                    = 1164000 J

or,                = 1164 kJ         (as 1 kJ = 1000 J)

Now, we will calculate the change in potential energy as follows.

             \Delta P.E = mg(z_{2} - z_{1})

                         = \rho \times V \times g (z_{2} - z_{1})

                         = 1000 \times 3 \times 9.7 (10 - 40)m

                         = -873000 J

or,                      = -873 kJ

Thus, we can conclude that change in  gravitational potential energy is -873 kJ.

4 0
3 years ago
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