1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
nikdorinn [45]
3 years ago
14

A wheel of mass 60.0 kg is pushed with a net force of 26.4 N. Find acceleration.

Physics
1 answer:
worty [1.4K]3 years ago
4 0

F= ma; a= F/m

a = 26.4 N/60 kg= 0.44 m/s^2

You might be interested in
If the object represented by the FBD below has a mass of 2.5 kg, what is the acceleration of the object?
Debora [2.8K]

Answer:

4 m/s² down

Explanation:

We'll begin by calculating the net force acting on the object.

The net force acting on the object from the left and right side is zero because the same force is applied on both sides.

Next, we shall determine the net force acting on the object from the up and down side. This can be obtained as follow:

Force up (Fᵤ) = 15 N

Force down (Fₔ) = 25 N

Net force (Fₙ) =?

Fₙ = Fₔ – Fᵤ

Fₙ = 25 – 15

Fₙ = 10 N down

Finally, we shall determine the acceleration of the object. This can be obtained as follow:

Mass (ml= 2.5 Kg

Net force (Fₙ) = 10 N down

Acceleration (a) =?

Fₙ = ma

10 = 2.5 × a

Divide both side by 2.5

a = 10 / 2.5

a = 4 m/s² down

Therefore, the acceleration of the object is 4 m/s² down

6 0
3 years ago
A solar cooker, really a concave mirror pointed at the sun, focuses the sun's rays 16.0 cm in front of the mirror. what is the r
VARVARA [1.3K]
The focal point of a concave mirror is halfway along the radius, therefore the radius would be 2•16= 32 cm
5 0
3 years ago
The park has added two more cars to the already existing roller coaster. If the park wants to maintain the speed of the roller c
vredina [299]
D because friction will slow it down going up hills (for safety reasons) and you go really fast going down.
7 0
3 years ago
Read 2 more answers
Using at least 3 to 4 complete content related sentences describe the first and second postulate of special relativity.
Andrew [12]
Nothing can travel faster than the speed of light. As such, perceptions of objects and time change as they approach light speed, but the laws of physics remain consistent regardless of speed. Objects will appear shortened and time will appear to slow down around an observer approaching near light speeds, but all quantities still exist as they did before and all causality is preserved, even if observers in different points or traveling at different speeds will report different things.
8 0
3 years ago
Read 2 more answers
After the collision, car 1 has a final velocity of 6m/s south. What is the final velocity of car2?
dedylja [7]
I’m almost 100 percent sure it’s the first one
4 0
3 years ago
Other questions:
  • Suppose a scientist doing an experiment in nuclear fusion starts out with twelve atoms. How many atoms will most likely result f
    15·1 answer
  • Write about a possible scenario where you may be tempted to not use lab safety explain what the correct and most safe choice wou
    5·1 answer
  • What is different about the different parts of the electromagnetic spectrum
    13·1 answer
  • Which electromagnetic waves have the shortest wavelength and the highest frequency? _________ waves
    8·2 answers
  • A 1100 kg automobile is at rest at a traffic signal. At the instant the light turns green, the automobile starts to move with a
    14·1 answer
  • As altitude increases in the troposphere and stratosphere, the air temperature
    10·1 answer
  • Can someone answer these questions
    11·2 answers
  • A car with a velocity of 15 m/s is accelerated uniformly at the rate of 1.9 m/s2 for 6.8 s. What is its final velocity?
    8·1 answer
  • Phys-1A Horizontal Practice 2
    6·1 answer
  • 3. Hahn determined that barium (atomic number 56) was one of the elements created when a uranium atom (atomic number 92) split .
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!