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Dmitry_Shevchenko [17]
3 years ago
10

The distance between pole and position of image can denoted by___a)u. b)v. c)R. d)C​

Physics
1 answer:
soldier1979 [14.2K]3 years ago
5 0

Answer:

b) v

Explanation:

the distance between pole and position of image can denoted by <u>v</u>

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a ray of light incident on a mirror, at an angle of 45°. Another mirror is placed at an angle of 45° to the first ones as shown.
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Answer:

If the ray of light is deflected by 45 degrees by the first mirror its total deflection by mirror (I) is 90 deg. (incident = 45 and exit ray equals 45 deg)

The second mirror will cause a net deflection of 90 degrees and the total deflection will be 180 deg or in opposite  direction to the  incident ray.

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X-rays are used instead of visible light because X-rays have shorter ______________ than visible light, allowing them to produce
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3 years ago
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A man walking on a tightrope carries a long a pole which has heavy items attached to the two ends. If he were to walk the tight-
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Answer:

 I_weight = M L²

this value is much larger and with it it is easier to restore balance.I

Explanation:

When man walks a tightrope, he carries a linear velocity, this velocity is related to the angular velocity by

            v = w r

For man to maintain equilibrium needs the total moment to be zero

             ∑τ = I α

              S  τ = 0

The forces on the home are the weight of the masses, the weight of the man and the support on the rope, the latter two are zero taque the distance to the center of rotation is zero.

Therefore the moment of the masses and the open is the one that must be zero.

If the man carries only the bar, we could approximate it by two open one on each side of the axis of rotation formed by the free of the rope

              I = ⅓ m L² / 4

As the length of half the length of the bar and the mass of the bar is small, this moment is small, therefore at the moment if there is some imbalance it is difficult to recover.

If, in addition to the opening, each of them carries a specific weight, the moment of inertia of this weight is

             I_weight = M L²

this value is much larger and with it it is easier to restore balance.

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2 years ago
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3 years ago
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A uniform, spherical, 1900.0 kg shell has a radius of 5.00 m. Find the gravitational force this shell exerts on a 1.80 kg point
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Answer:

F=9.09\times 10^{-9} N

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Because distance measure from center .

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