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Slav-nsk [51]
3 years ago
6

Select the correct answer.

Physics
1 answer:
Nina [5.8K]3 years ago
3 0

Answer:

Ос.

The spacing between particles increases.

Heat causes greater particle activity, and the particles

are farther apart.

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A package was determined to have a mass of 5.7 kilograms. What's the force of gravity acting on the package on earth?
Arturiano [62]
1.) The force of gravity is what we call weight, we define it as:
w=mg
w=5,7kg*9,8m/s²
w=55,86kg (b)
2.) We know that:
power=W/t
power=50J/20s
power=2,5Watts (a)
3.) The work done is equal to the potential energy, so:
Epg=mgh
Epg=63kg*9,8m/s²*7m
Epg=4321J
Now we get the power:
power=W/t
power=4321J/5s
power=864Watts
Now:
1HP=746Watts
=1,16HP (b)
4.) We know that:
F=ma
350N=m*10m/s²
m=350N/10m/s²
m=35kg (b)
5.) d.) Aceleration is tha rate of change in velocity, either positive (increasing) or negative (decreasing)
8 0
3 years ago
Read 2 more answers
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Kamila [148]

The two basic defenses in basketball are man-to-man, sometimes referred to as person-to-person in respect for the rise of women's basketball, and zone. Each basic defense has a number of variations.

4 0
3 years ago
Distinguish between speed and velocity
Vanyuwa [196]
Velocity is a vector quantity, follows law of vector addition, has both direction and magnitude while speed is a scalar quantity , follows law of algebra and only has magnitude
4 0
3 years ago
A bulldozer does 4,500 J of work to push a mound of soil to the top of a ramp that is 15 m high. The ramp is at an
vivado [14]

Answer:

520 N

Explanation:

Work is the dot product of the force vector and displacement vector.

W = F · x

This means it is the product of the magnitudes of the vectors and the cosine of the angle between them.

W = F x cos θ

The displacement of the soil is 15 m up.  The force is parallel to the ramp.  So the angle between the vectors is 90° − 35° = 55°.

Plugging in the values and solving for F:

4500 J = F (15 m) (cos 55°)

F = 523 N

Rounded to two significant figures, the force is 520 N.

6 0
4 years ago
A system consists of two positive point charges, q1 and q2>q1. The total charge of the system is 68.0 μC , and each charge ex
vaieri [72.5K]

Answer:

q₁ = +12.19 μC

q₂ = +55.81 μC

Explanation:

From Coulomb's law,

                                 F = k\frac{q_{1}q_{2}}{r^{2}}

Where,

F is the electrostatic force

k is the constant of proportionality 9 × 10⁹ Nm²/C²

q₁ and q₂ are the point charges

r is the distance between the charges

                         84 = 9 * 10^{9}\frac{q_{1}q_{2}}{0.270^{2}}

                         q_{1}q_{2} = \frac{84 * 0.270^{2}}{9 * 10^{9}}  

                         q₁q₂ = 6.804 × 10 ⁻¹⁰ C

                         q₁q₂ = 0.6804 × 10 ⁻⁹ C     -------(1)  

Also, the total charge of the system is 68.0 μC

                   ⇒   q₁ + q₂ = 68.0 μC  

For simplicity,    q₁ + q₂ = 68 × 10⁻⁶  C      --------(2)  

Solving equation 1 and 2 simultaneously using substitution method. From equation 2,        

                          q₂ = 68 × 10⁻⁶ - q₁          ---------(3)

Substituting equation (3) into (1)

                          q₁(68 × 10⁻⁶ - q₁) = 0.6804 × 10 ⁻⁹

                          68 × 10⁻⁶q₁ - q₁² = 0.6804 × 10 ⁻⁹

                         q₁² - 68 × 10⁻⁶q₁ + 0.6804 × 10 ⁻⁹ = 0

solving the quadratic equation using quadratic formula,    

a = 1, b = - 68 × 10⁻⁶, c = 0.6804 × 10 ⁻⁹

                  q_{1} = \frac{-b \± \sqrt{b^{2} - 4ac} }{2a}

                 q_{1} = \frac{-(- 68 *  10^{-6}) \± \sqrt{(- 68 * 10^{-6})^{2} - (4*1*0.6804*10^{-9}})}{2*1}

                 q₁ = +12.19 μC  or  +55.81 μC

Testing for the two q₁ to get q₂

When q₁ = +12.19 μC

                   12.19 μC  + q₂ = 68.0 μC      

                    q₂ = 68.0 μC  - 12.19 μC

                    q₂ = +55.81 μC

When  q₁ = +55.81 μC

                  55.81 μC  + q₂ = 68.0 μC      

                    q₂ = 68.0 μC  - 55.81 μC

                    q₂ = +12.19 μC  

We have two possible solutions for the question.

         When q₁ = +12.19 μC, q₂ = +55.81 μC   and

         When q₁ = +55.81 μC, q₂ = +12.19 μC

Considering the conditions given in the system,

(1) Two positive point charges q₁ and q₂

(2) Charge q₂ is greater than charge q₁,  q₂>q₁

The solution that satisfies the condition is q₁ = +12.19 μC, q₂ = +55.81 μC

4 0
3 years ago
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