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Inessa05 [86]
3 years ago
6

From an aerial photograph, one observes that on a level section of a (multilane) highway, 25% of the vehicles are trucks, 75% ar

e cars, and there are 50 vehicles per mile of highway. The trucks travel at 40 mph and the cars at 60 mph. This highway also has a section with a steep grade on which the speed of the trucks drops to 25 mph and the speed of the cars to 55 mph. No vehicles enter or exit the subject highway sections (except at the ends). The flows on these highwaysections are stationary, which means that the flows on the level section are equal to those on the grade. Determine
(a) the flow of vehicles on the level section;
(b) the density of vehicles on the grade;
(c) the percent of trucks on the grade as seen from an aerial photo; (d) the percent of trucks as seen by a stationary observer on the grade.
Engineering
1 answer:
egoroff_w [7]3 years ago
4 0

Answer:

(a) Flow rate of vehicles = No of vehicles per mile * Speed

=No of cars per mile * Speed +No of trucks per mile * Speed

= 0.75*50*60 + 0.25*50*40

=2750 vehicles / hour

(b) Let Density of vehicles on grade = x

Density on flat * Speed =Density on grade * Speed

So,( 0.75*50) * 60 + (0.25*50) * 40 = (0.75* x) * 55 + (0.25* x) * 25

So, x= 57.89

So, Density is around 58 Vehicles per Mile.

(c) Percentage of truck by aerial photo = 25%

(d)Percentage of truck bystationary observer on the grade= 25*30/60 * 25/55 =22.73 %

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While supporting load P, the maximum contraction permitted in a 4.75-m long pipe column is 7 mm. Given that E =180 GPa for the c
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Answer:

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From the concept of Hooke's  Law,

E =\dfrac{ stress \ \sigma}{ strain \  \varepsilon}

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strain \ \varepsilon =0.00147368

Recall:

E =\dfrac{ stress \ \sigma}{ strain \  \varepsilon}

stress \ \sigma = E \times { strain \  \varepsilon}

stress \ \sigma = 180 \times 10^{3} \ Mpa \times 0.00147

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3 years ago
What is 220 C in degrees Fahrenheit (F)?
8_murik_8 [283]

Answer:

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Explanation:

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A diesel engine with CR= 20 has inlet at 520R, a maximum pressure of 920 psia and maximum temperature of 3200 R. With cold air p
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Answer:

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If we assume that in diesel engine all process is adiabatic then

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\dfrac{T_2}{520}=20^{1.4 -1}

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