A _____ satellite system employs many satellites that are spaced so that, from any point on the Earth at any time, at least one
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Answer:
We are given:
Elevation of PVI = 471.00ft
Vertical curve = 1400ft
Rising grade, G1=2.5℅
Falling grade, G2= 1.5℅
at a 100 00 station
a) Let's find PVC and PVT elevation,
•PVC elevation = PVI- g1
471.00 - (2.5/100)(700) = 453.5ft
•PVT elevation = PVI +g2
= 471 +(1.5/100)700 = 460.5ft
For mid-ordinate, we have:
L/8 * (G2 + G1)
= (1400/8)[(1.5+2.5)/100] = 7ft
Mid-ordinate= 7ft
b) •station PVC = PVI - L/2
= (100+00) - (14/2 +00)
= 93 + 00
• Station PVT = PVI + L/2
= (100+00)+(14/2 + 00)
= 107 + 00
Let's find the elevation at PVI stations before,
PVI = elevation of PVI - g1(distance between PVI and station)
= 471 - 2.5℅ * [(100+00) - (94+00)]
= 471 -2.5℅*(6+00)
= 471 -2.5℅ *600ft
= 456ft
Let's now find elevation of station after PVI,
Elevation = PVI-g2
= 471-1.5℅[(101+00)-(100-00)]
= 471-1.5℅(1+00)
= 471-1.5℅*(100) = 469.5ft
After calculating, we have .....Station....... Elevation
PVC=> 93+00. 453.5
94+00. 456
95+00. 458.5
96+00. 461
97+00 463.5
98+00. 466
99+00. 466.85
PVI=> 100+00. 471
101+00. 469.5
102+00. 468
103+00. 466.5
104+00. 465
105+00. 463.5
106+00. 463
PVI=> 107+00. 460.5
(100+00) => 100chains
If 1 chain = 100ft
Then, (101+00) = 110 chains
= (101+00) = 110*100ft
